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[英]How do I return an array of objects with certain conditions in Javascript?
[英]How do I return an array of objects that only contains a certain object in an array for Javascript?
我有一個稱為演員的 object 數組:
const actors = [{
"name": "John Doe",
"rating": 1234,
"alternative_name": null,
"objectID": "551486300"
},
{
"name": "Jane Doe",
"rating": 4321,
"alternative_name": "Monica Anna Maria Bellucci",
"objectID": "551486310"
}];
我特別想知道演員的名字和收視率。 我嘗試通過制作一個名為 actorNameRating 的 function 來獲得它,但我的代碼不起作用。
const nameAndRating = function() {
const actorName = nameAndRating.filter(name);
return actorName;
const actorRating = nameAndRating.filter(rating);
return actorRating;
};
返回后的任何事情都不會執行,您可以將兩個值作為一個字符串返回,然后將其分開,例如:
const nameAndRating = function() {
const actorName = nameAndRating.filter(name);
const actorRating = nameAndRating.filter(rating);
return actorName+","+actorRating;
};
或您認為更適合您使用的任何其他方式
您可以通過map和 function 並僅返回名稱和評級:
const actors = [{ "name": "John Doe", "rating": 1234, "alternative_name": null, "objectID": "551486300" }, { "name": "Jane Doe", "rating": 4321, "alternative_name": "Monica Anna Maria Bellucci", "objectID": "551486310" }]; const nameAndRating = function() { return actors.map(actor => ({ name: actor.name, rating: actor.rating })) }; console.log(nameAndRating())
您可以為此簡單地使用Array.map
:
const actors = [{ "name": "John Doe", "rating": 1234, "alternative_name": null, "objectID": "551486300" }, { "name": "Jane Doe", "rating": 4321, "alternative_name": "Monica Anna Maria Bellucci", "objectID": "551486310" }]; let result = actors.map(({name, rating}) => ({name, rating})); console.log(result);
或者,如果您希望它們在兩個單獨的 arrays 中,則可以使用通用 function 來返回給定道具的值數組:
const actors = [{ "name": "John Doe", "rating": 1234, "alternative_name": null, "objectID": "551486300" }, { "name": "Jane Doe", "rating": 4321, "alternative_name": "Monica Anna Maria Bellucci", "objectID": "551486310" }]; let getPropValues = (arr, prop) => arr.map(o => o[prop]); console.log("Names = ",getPropValues(actors, "name")); console.log("Ratings = ",getPropValues(actors, "rating"));
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