如何 append 從用戶輸入到列表和字典，並在 python 中用分隔符 (;;;) 分隔？

Question

myDict = {'Name': ['Daniel', 'Melissa', 'Vicky', 'Winona'],
         'Tribe': ['Bataknese', 'Javanese', 'Bataknese', 'Javanese'],
         'Town': ['Indramayu', 'Jakarta', 'Jakarta', 'Batam'],
         'Username': ['dan.iel', 'melissaaaa', 'vic.ky', 'weenonuhh']}

myList = [['Daniel', 'Bataknese', 'Indramayu', 'dan.iel'],
         ['Melissa', 'Javanese', 'Jakarta', 'melissaaaa'],
         ['Vicky', 'Bataknese', 'Jakarta', 'vic.ky'],
         ['Winona', 'Javanese', 'Batam', 'weenonuhh']]

如何使 function 向字典和列表添加/附加更多值？

def add(something):
    ....

 add('Clara Angela;;;Balinese;;;Bali;;;clara123')

那么，myDict 和我的 List 應該是這樣的：

myDict = {'Name': ['Daniel', 'Melissa', 'Vicky', 'Winona','Clara Angela'],
         'Tribe': ['Bataknese', 'Javanese', 'Bataknese', 'Javanese','Balinese'],
         'Town': ['Indramayu', 'Jakarta', 'Jakarta', 'Batam','Bali'],
         'Username': ['dan.iel', 'melissaaaa', 'vic.ky', 'weenonuhh','clara123']}

myList = [['Daniel', 'Bataknese', 'Indramayu', 'dan.iel'],
         ['Melissa', 'Javanese', 'Jakarta', 'melissaaaa'],
         ['Vicky', 'Bataknese', 'Jakarta', 'vic.ky'],
         ['Winona', 'Javanese', 'Batam', 'weenonuhh'],
         ['Clara Angela', 'Balinese', 'Bali', 'clara123']]

Answer 1

假設順序正確； 使用str.split和 append 到myList ，然后循環myDict.values()附加每個值（ zip將很方便） ：

def add(data):
    data = data.split(';;;')
    myList.append(data)
    for l, v in zip(myDict.values(), data):
        l.append(v)

add('Clara Angela;;;Balinese;;;Bali;;;clara123')

結果：

我的字典

{'Name': ['Daniel', 'Melissa', 'Vicky', 'Winona', 'Clara Angela'],
 'Town': ['Indramayu', 'Jakarta', 'Jakarta', 'Batam', 'Bali'],
 'Tribe': ['Bataknese', 'Javanese', 'Bataknese', 'Javanese', 'Balinese'],
 'Username': ['dan.iel', 'melissaaaa', 'vic.ky', 'weenonuhh', 'clara123']}

我的列表

[['Daniel', 'Bataknese', 'Indramayu', 'dan.iel'],
 ['Melissa', 'Javanese', 'Jakarta', 'melissaaaa'],
 ['Vicky', 'Bataknese', 'Jakarta', 'vic.ky'],
 ['Winona', 'Javanese', 'Batam', 'weenonuhh'],
 ['Clara Angela', 'Balinese', 'Bali', 'clara123']]

如果您不使用 Python 3.X ，其中 dict 是有序的，那么operator.itemgetter是您的下一個最佳選擇：

get_lists = itemgetter('Name', 'Tribe', 'Town', 'Username')
for l, v in zip(get_lists(myDict), data):
    ...

Answer 2

這是一個可以做到這一點的代碼：

myDict = {'Name': ['Daniel', 'Melissa', 'Vicky', 'Winona'],
         'Tribe': ['Bataknese', 'Javanese', 'Bataknese', 'Javanese'],
         'Town': ['Indramayu', 'Jakarta', 'Jakarta', 'Batam'],
         'Username': ['dan.iel', 'melissaaaa', 'vic.ky', 'weenonuhh']}

def add ( Name, Tribe, Town, Username):
    myDict["Name"].append(Name)
    myDict["Tribe"].append(Tribe)
    myDict["Town"].append(Town)
    myDict["Username"].append(Username)

add("Clara Angela","Balinese","Bali","clara123")

print(myDict)

output 將是：

{'Name': ['Daniel', 'Melissa', 'Vicky', 'Winona', 'Clara Angela'],
 'Tribe': ['Bataknese', 'Javanese', 'Bataknese', 'Javanese', 'Balinese'],
 'Town': ['Indramayu', 'Jakarta', 'Jakarta', 'Batam', 'Bali'],
 'Username': ['dan.iel', 'melissaaaa', 'vic.ky', 'weenonuhh', 'clara123']}

但是，如果輸入應該是您要求的方式，則將代碼修改為：

myDict = {'Name': ['Daniel', 'Melissa', 'Vicky', 'Winona'],
         'Tribe': ['Bataknese', 'Javanese', 'Bataknese', 'Javanese'],
         'Town': ['Indramayu', 'Jakarta', 'Jakarta', 'Batam'],
         'Username': ['dan.iel', 'melissaaaa', 'vic.ky', 'weenonuhh']}
def add (i):
    j=i.split(";;;")
    myDict["Name"].append(j[0])
    myDict["Tribe"].append(j[1])
    myDict["Town"].append(j[2])
    myDict["Username"].append(j[3])
add(i)    
print(myDict)

Answer 3

你可以做：

    myDict = {'Name': ['Daniel', 'Melissa', 'Vicky', 'Winona'],
             'Tribe': ['Bataknese', 'Javanese', 'Bataknese', 'Javanese'],
             'Town': ['Indramayu', 'Jakarta', 'Jakarta', 'Batam'],
             'Username': ['dan.iel', 'melissaaaa', 'vic.ky', 'weenonuhh']}

    myList = [['Daniel', 'Bataknese', 'Indramayu', 'dan.iel'],
             ['Melissa', 'Javanese', 'Jakarta', 'melissaaaa'],
             ['Vicky', 'Bataknese', 'Jakarta', 'vic.ky'],
             ['Winona', 'Javanese', 'Batam', 'weenonuhh']]

    def add(my_string):
        splitted = my_string.split(';;;')
        myList.append(splitted)
        for i, item in enumerate(['Name', 'Tribe', 'Town', 'Username']):
            myDict[item].append(splitted[i])

    add('Clara Angela;;;Balinese;;;Bali;;;clara123')