如何根據python中geoJSON文件的更新版本制作新文件？

Question

我一直在嘗試更新一個大型 geoJSON 文件，我想將所有 NAME_1 更新為小寫並將其保存在一個新文件中，有什么想法嗎？

這是我的 geoJSON 文件的一部分 有大量坐標，所以我只是將其切斷並使其成為....以簡化此處的帖子 對於 NAME_1 變量實際上大約有 32 個，我切斷了兩個只是為了簡化目的，但我需要更新所有 32

{
  "type": "FeatureCollection",
  "features": [
    {
      "type": "Feature",
      "geometry": {
        "type": "MultiPolygon",
        "coordinates": [
          [
            [
              [
                ......
             ]
            ]
          ]
        ]
      },
      "properties": {
        "GID_0": "IND",
        "NAME_0": "India",
        "GID_1": "IND.1_1",
        "NAME_1": "Andaman and Nicobar",
        "VARNAME_1": "Andaman & Nicobar Islands|Andaman et Nicobar|Iihas de Andama e Nicobar|Inseln Andamanen und Nikobare",
        "NL_NAME_1": "",
        "TYPE_1": "Union Territor",
        "ENGTYPE_1": "Union Territory",
        "CC_1": "",
        "HASC_1": "IN.AN"
      }
   },
      {
      "type": "Feature",
      "geometry": {
        "type": "MultiPolygon",
        "coordinates": [
          [
            [
              [
                ......
              ]
            ]
          ]
        ]
      },
      "properties": {
        "GID_0": "IND",
        "NAME_0": "India",
        "GID_1": "IND.2_1",
        "NAME_1": "Andhra Pradesh",
        "VARNAME_1": "",
        "NL_NAME_1": "",
        "TYPE_1": "State",
        "ENGTYPE_1": "State",
        "CC_1": "",
        "HASC_1": "IN.AP"
      }

我的代碼：

import sys
from geojson import Feature, Point, FeatureCollection, Polygon
import json
import geojson
import pprint
import pandas as pd
import re
import os
#print(sys.version)

with open('gadm36_IND_1.json', 'r') as data_file:
    data = json.load(data_file)

for feature in data['features']:
    #change all the Name_1 into lowercase
    name1 = feature['properties']['NAME_1']
    for f in re.findall("([A-Z]+)", name1):
        name1 = name1.replace(f, f.lower())

with open('lower.json', 'w+') as data_file:
    json.dump(data, data_file, indent=2)

請快速幫助嘿嘿嘿

Answer 1

您需要在原始data['features']中設置值。

因此，在name1 = name1.replace(f, f.lower())行中替換為feature['properties']['NAME_1'] = name1.replace(f, f.lower()) 。

另一種方法是在第二個循環中添加這一行： feature['properties']['NAME_1'] = name1 。

Answer 2

假設您要轉換特征數組中所有對象的鍵NAME_1的值。

import sys
import json
import re
import os

with open('gadm36_IND_1.json', 'r') as data_file:
    data = json.load(data_file)

for feature in data['features']:
    # change all the Name_1 into lowercase
    feature['properties']['NAME_1'] = feature['properties']['NAME_1'].lower()

with open('lower.json', 'w+') as data_file:
    json.dump(data, data_file, indent=2)

此代碼將鍵NAME_1的值轉換為小寫並將新數據寫入文件lower.json

下面是我的lower.json樣子：

{
  "type": "FeatureCollection",
  "features": [
    {
      "type": "Feature",
      "properties": {
        "GID_0": "IND",
        "NAME_0": "India",
        "GID_1": "IND.1_1",
        "NAME_1": "andaman and nicobar",
        "VARNAME_1": "Andaman & Nicobar Islands|Andaman et Nicobar|Iihas de Andama e Nicobar|Inseln Andamanen und Nikobare",
        "NL_NAME_1": "",
        "TYPE_1": "Union Territory",
        "ENGTYPE_1": "Union Territory",
        "CC_1": "",
        "HASC_1": "IN.AN"
      }
    },
    {
      "type": "Feature",
      "properties": {
        "GID_0": "IND",
        "NAME_0": "India",
        "GID_1": "IND.2_1",
        "NAME_1": "andhra pradesh",
        "VARNAME_1": "",
        "NL_NAME_1": "",
        "TYPE_1": "State",
        "ENGTYPE_1": "State",
        "CC_1": "",
        "HASC_1": "IN.AP"
      }
    }
  ]
}

希望能幫助到你！

Answer 3

使用正則表達式

with open('gadm36_IND_1.json') as data_file:
    Json_Str = data_file.read()
NAME_REGEX = re.compile(r'\"NAME_1\":\s*\"(.*?)\"')
for name in NAME_REGEX.findall(Json_Str):
    Json_Str = Json_Str.replace(name , name.lower())

現在您有一個修改后的 Json 字符串，您可以輕松地將其轉換為 json obj