[英]How to find all occurrences of a string?
嗨，我在嘗試代碼時遇到問題，但我失敗了
HTML
<a href="http://wwwgoogg.com/asas/1.mkv">download</a>
<a href="http://wwwgoogg.com/asas/12.mkv">download</a>
<a href="http://wwwgoogg.com/asas/13.mkv">download</a>
<a href="http://wwwgoogg.com/asas/16.mkv">download</a>
<a href="http://wwwgoogg.com/asas/22.mkv">download</a>
腳本
// ==UserScript==
// @name New Userscript
// @match file:///E:/Physics.html
// ==/UserScript==
/* global $ */
(function() {
var full1 = document.body.innerHTML
var first1 = full1.indexOf("wwwgoogg");
var first2 = full1.slice(first1);
var last1 = first2.indexOf("mkv");
var aa1 = full1.substring((last1-2+first1),(first1));
alert (aa1);
})();
wwwgoogg.com/asas/1.mkv
wwwgoogg.com/asas/12.mkv
wwwgoogg.com/asas/221.mkv
wwwgoogg.com/asas/133.mkv
提前致謝
我已經定義了一個正則表達式並在全球范圍內應用它。 答案請看控制台
var testStr = "<a href='http://wwwgoogg.com/asas/1.mkv'>download</a> <a href='http://wwwgoogg.com/asas/12.mkv'>download</a> <a href='http://wwwgoogg.com/asas/13.mkv'>download</a> <a href='http://wwwgoogg.com/asas/16.mkv'>download</a> <a href='http://wwwgoogg.com/asas/22.mkv'>download</a>" var regex = /wwwgoogg/gi; var result; var indices = []; while ((result = regex.exec(testStr))) { indices.push(result.index); } console.log(indices);
<!DOCTYPE html>
<html>
<body>
<a class="input" href="http://wwwgoogg.com/asas/1.mkv">download</a>
<a class="input" href="http://wwwgoogg.com/asas/12.mkv">download</a>
<a class="input" href="http://wwwgoogg.com/asas/13.mkv">download</a>
<a class="input" href="http://wwwgoogg.com/asas/16.mkv">download</a>
<a class="input" href="http://wwwgoogg.com/asas/22.mkv">download</a>
<a class="input" href="http://wwwgoogg.com/asas/22.mkv">download</a>
<a class="input" href="http://wwwgoogg.com/asas/22.mkv">download</a>
<a class="input" href="http://wwwgoogg.com/asas/22.mkv">download</a>
<a class="input" href="http://wwwgoogg.com/asas/22.mkv">download</a>
<a class="input" href="http://wwwgoogg.com/asas/22.mkv">download</a>
<a class="input" href="http://wwwgoogg.com/asas/22.mkv">download</a>
<a class="input" href="http://wwwgoogg.com/asas/22.mkv">download</a>
<a class="input" href="http://wwwgoogg.com/asas/22.mkv">download</a>
</body>
</html>
和代碼
// ==UserScript==
// @name New Userscript
// @match file:///E:/Physics.html
// @grant GM_openInTab
// ==/UserScript==
/* global $ */
(function() {
var x = document.getElementsByClassName("input").length;
var i ;
for (i = 0; i < x; i++) {
var fields = document.getElementsByClassName("input")[i].getAttribute('href');
GM_openInTab(fields);
}
//var bb = document.getElementsByClassName("input")[i].getAttribute('href');
// GM_openInTab (bb);
})();
這就是我想要的，非常感謝你幫助我，我真的很感激，我學到了很多，我正在學習
您可以將 HTML 文本與 RegExp 匹配並獲得所有結果。 請參見以下示例：
const text = ` <a href="http://wwwgoogg.com/asas/1.mkv">download</a> <a href="http://wwwgoogg.com/asas/12.mkv">download</a> <a href="http://wwwgoogg.com/asas/13.mkv">download</a> <a href="http://wwwgoogg.com/asas/16.mkv">download</a> <a href="http://wwwgoogg.com/asas/22.mkv">download</a> `; const matches = text.match(/https?:\/\/wwwgoogg.com\/[\w/.]+/gm); console.log(matches);
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