簡體   English   中英

@Formula 從 spring 數據 jpa 中的 @OneToMany 關聯中計算 object

[英]@Formula to count object from a @OneToMany association in spring data jpa

In a java rest api, with spring boot, and spring-dta-jpa, db is postgresql I have a Book entity that contains bookCopies . 這些bookCopies可能可用或不可用。 我正在嘗試用可用的副本數檢索這本書。 書籍可以按書名或作者姓名搜索。

我設法通過在我的書實體中添加一個@Transient字段來獲取信息,並在getNbCopiesAvailable()方法上使用@Transient注釋,但我被要求使用@Formula注釋來完成,我不知道如何去做吧。

我實際上遇到了一個錯誤:

org.postgresql.util.PSQLException: ERREUR: plus d'une ligne renvoyée par une sous-requête utilisée comme une expression 
// which means that several lines are sent by the sub-query

這是我的實體:

@Entity
@Getter
@Setter
@NoArgsConstructor
public class Book {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;
    private String isbn;
    @NotNull
    private String title;

    @JsonIgnore
    @OneToMany(mappedBy = "book", cascade = CascadeType.ALL, orphanRemoval = true)
    private List<BookCopy> copyList = new ArrayList<>();

    @NotNull
    @ManyToMany(cascade = {CascadeType.PERSIST, CascadeType.MERGE})
    @JoinTable(name = "book_author",
               joinColumns = @JoinColumn(name = "book_id"),
               inverseJoinColumns = @JoinColumn(name = "author_id"))
    private Set<Author> authors = new HashSet<>();

    @Formula("(SELECT COUNT(bc.id) FROM book b left join book_copy bc on bc.book_id = b.id  WHERE bc.available = 'true' GROUP BY b.id)")
    private Long nbCopiesAvailable;


@Entity
@Getter
@Setter
@Builder
@AllArgsConstructor
public class BookCopy {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;
    private String barcode;
    private String editor;
    private boolean available = true;

    @ManyToOne(fetch = FetchType.LAZY)
    private Book book;

這是我的存儲庫,其中包含按標題和作者檢索書籍的查詢:

    @Query("select b, a from Book b join b.authors a where b.title like %:title% and concat(a.firstName, ' ', a.lastName) like %:author%")
    List<Book> findByTitleAndAuthor(@Param("title")String title,@Param("author") String author);

@Formula("(SELECT COUNT(bc.id) FROM book b left join book_copy bc on bc.book_id = b.id WHERE bc.available = 'true' GROUP BY b.id)")很難寫語法錯誤,混合原生 sql 和 jpql 對我來說很奇怪。 但是,如果我嘗試在@Formula中編寫 @Formula 它根本不起作用。

我檢查了這個最接近我的問題的主題( @Formula count on ManyToMany ),但它仍然不起作用。

您需要在 where 子句中引用該書:

@Formula("(SELECT COUNT(bc.id) FROM book b " +
         "left join book_copy bc on bc.book_id = b.id " +
         "WHERE bc.available = 'true' " +
         "and b.id = id " + // This is the important condititon
         "GROUP BY b.id)")
private Long nbCopiesAvailable;

否則,您的查詢將返回所有書籍。

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM