[英]Why does my “for” loop run only two times?
我正在做的任務是輸入 5 個 5 位隨機數,壓縮它們並得到它們的總和。 那么我們如何壓縮它們呢? 我們去掉了第二個和第四個數字。 例如 12345 到 10305。
這是我的代碼。
int main()
{
int n=5,i,j,number5,num1,num3,numb5,sum;
for(i=0;i<n;i++) // 5 times we read next for loop right ?
for(j=0;j<i;j++){ // this loop read 5 times 5 digits number
scanf("%d",&number5); // scanf 1 number
while(number5){ // while number isn't 0 ( false )
num1=number5/10000;
num1*=10000;
num3=(number5%10000)%1000/100;
num3*=100;
numb5=(number5%10000)%1000%100%10;
numb5*=1;// mathematic operations to get to 1st third and 5th number
number5=0; // set the number5 to 0 so we can go out of while right ?
}
sum=num1+num3+numb5; // we get the sum of the first 5 digits and we get it on the second when j++ right ?
}
printf("%d",sum);// on the end of all five number with 5 digits we get the sum right ?
}
那么為什么我for
循環只運行兩次而不是五次呢?
這個你真的想多了。
int n;
for(int i=0; i < 5; ++i)
{
// read first number eg 12345
scanf("%d",&n);
int d1 = n % 10; // ones place = 5
n /= 100; // n becomes 123
int d100 = n % 10; // hundreds place = 3
n /= 100; // n becomes 1
int d10000 = n % 10; // ten thousands place = 1
int smallSum = 100*d10000 + 10*d100 + d1;
// prints 135
printf("sum version 1 = %d\n", smallSum);
int bigSum = 10000*d10000 + 100*d100 + d1;
// prints 10305
printf("sum version 2 = %d\n",bigSum);
}
只需在第二個循環中將j<i
設為j<5
,您就可以得到五個 5 位壓縮數字的總和n
次。
我在片段中提到的錯誤是唯一的問題 rest 一切都很好。 請參閱附加的片段。
// only two loops are required
for(int i=0;i<5;i++){
scanf("%d",&number5);
sum=0;
while(number5){
num1=number5/10000;
num1*=100;//it should be 100 isntead of 10000
num3=(number5%10000)%1000/100;
num3*=10;// it should be 10 istead of 100
numb5=(number5%10000)%1000%100%10;
numb5*=1;
number5=0;
}
sum=num1+num3+numb5;
printf("%d\n",sum);
}
#include <stdio.h>
#include <stdlib.h>
int main()
{
int n=5,i,j,number5,num1,num3,numb5;
int sum=0;
for(i=0;i<n;i++) {
scanf("%d",&number5);//runs 5 times to get 5 inputs
sum+=(number5/10000)*10000; // take the value of first position
sum+=((number5/100)%10)*100; // take the value of third position
sum+=(number5%10);// take the value of fifth position
}
printf("%d",sum);
}
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.