[英]Get missing date values from array in php dynamically
我們正在創建一個系統,員工需要更新他們的每日狀態報告。 該系統的基本目的是記錄他們沒有更新狀態報告的缺失日期。
我找到了一種方法,通過檢查 2 個數組值之間的天差,然后計算並顯示天數。 但是,我不確定如何在 2 個數組值之間動態執行此操作。
這是我與輸出一起使用的代碼:
//id of the person updating the DSR
$userid = $_id;
// Array to fetch all the DSR by specific user
$fine = getDSRbyUserIdOrderDate($userid);
$today = date('d-m-Y');
$tomorrow = date("d-m-Y", strtotime($today . " +1 day"));
$ok = count($fine) - 1;
//Array to get dates
$d1 = $fine[0]['date'];
$d2 = $fine[1]['date'];
$d3 = $fine[2]['date'];
// Function call to find date difference
$dateDiff = dateDiffInDays($d1, $d2);
$dateDiff1 = dateDiffInDays($d2, $d3);
echo "<h4 style='color:red'>You have missed the DSR on the following dates.</h4>";
for($p = 1; $p < $dateDiff; $p++){
$missingdate = date("d-m-Y", strtotime($d1 . " +$p day"));
echo "<span style='color:red'>$missingdate</span>";
echo "<br />";
}
for($p = 1; $p < $dateDiff1; $p++){
$missingdate = date("d-m-Y", strtotime($d2 . " +$p day"));
echo "<span style='color:red'>$missingdate</span>";
echo "<br />";
}
if($d2 != $today){
echo "<span style='color:red'>$today <i>- Kindly update DSR before midnight</i></span> ";
echo "<br />";
}
我會首先按日期創建一個條目列表,然后相應地“繪制”它。
$starting_date = new DateTime('2019-11-23');
$num_days = 10
$from_db_by_date = [];
foreach ($fine as $entry) {
$from_db_by_date[$entry['date']] = $entry;
}
$all_by_date = [];
for ($i = 0; $i < $num_days; $i++) {
$date_str = $starting_date->format('d-m-Y');
$all_by_date[$date_str] = $from_db_by_date[$date_str] ?: null;
$starting_date->modify('+1 day');
}
現在您可以遍歷$all_by_date
,檢查條目是否為null
並采取相應措施。
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