在 PHP 中驗證數據庫中的用戶名和密碼后，如何使按鈕轉到特定頁面

Question

我一直在嘗試讓按鈕在驗證用戶輸入正確的用戶名/密碼后轉到頁面，我已經部分完成了，問題是當我單擊按鈕時它不會驗證用戶名/password，它只會轉到位置。 我正在使用 HTML、CSS、javascript 和 PHP。 這是代碼。

<?php
// include database and object files
include_once '../config/database.php';
include_once '../objects/user.php';

// get database connection
$database = new Database();
$db = $database->getConnection();

// prepare user object
$user = new User($db);
// set ID property of user to be edited
$user->username = isset($_GET['username']) ? $_GET['username'] : die();
$user->password = base64_encode(isset($_GET['password']) ? $_GET['password'] : die());
// read the details of user to be edited
$stmt = $user->login();
header('Location: ../../../../Home/index.html');
if($stmt->rowCount() > 0){
    // get retrieved row
    $row = $stmt->fetch(PDO::FETCH_ASSOC);
    // create array
    $user_arr=array(
        "status" => true,
        "message" => "Successfully Login!",
        "id" => $row['id'],
        "username" => $row['username']
    );
}
else{
    $user_arr=array(
        "status" => false,
        "message" => "Invalid Username or Password!",
    );
}
// make it json format
print_r(json_encode($user_arr));
?>

這是一個視頻... https://youtu.be/Li__rDSdEbs

Answer 1

問題是您在獲取用戶數據之前定位到另一個頁面，

if($stmt->rowCount() > 0){
// get retrieved row
$row = $stmt->fetch(PDO::FETCH_ASSOC);
// create array
$user_arr=array(
    "status" => true,
    "message" => "Successfully Login!",
    "id" => $row['id'],
    "username" => $row['username']
);
header('Location: ../../../../Home/index.html');}