[英]Exact regex match with ampersand words
我如何不能僅將“軟件”與“軟件和框架”相匹配?
$skill = array("software & framework","communication skills","technology-based","software","technology");
$text = "software & framework and technology-based and excel technology- communication";
foreach ($skill as $skills) {
preg_match_all("~(?<![\w-])" . preg_quote($skills) . "(?![\w-])~i", $text, $matchWords);
foreach ($matchWords[0] as $matchWord) {
echo "<b>MatchWord:</b> " . $matchWord. "<br>";
}
當前結果:
預期成績:
您需要動態構建帶有交替的單個模式:
$pattern = '~(?<![\w-])(?:' . implode('|', array_map(function($i) {
return preg_quote($i, '~');
}, $skill)) . ')(?![\w-])~i';
然后,您可以提取匹配項:
if (preg_match_all($pattern, $text, $matchWords)) {
print_r($matchWords[0]);
}
輸出: Array ([0] => software & framework [1] => technology-based )
注意 :如果未按長度將$skill
數組中的迭代按長度降序排序,則需要使用以下方法進行此操作,例如:
usort($skill, function($a, $b) {
return strlen($b) - strlen($a);
});
查看完整的PHP演示 。
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