按值過濾對象數組

Question

我希望迭代一array objects ，這里為了說明的目的是Users 。 我想使用提供的搜索詞和每個objects屬性的值來過濾這些Users 。

我提出了以下可行的解決方案，但是，我想看看是否有人有更優雅的方法？

let users = [
  {
    first_name: "Super",
    last_name: "User"
  },
  {
    first_name: "Admin",
    last_name: "Istrator"
  }
];

function filterObjects(collection, term) {
  let filtered = [];
  _.each(collection, obj => {
    _.forOwn(obj, (value, key) => {
      if (value.includes(term)) {
        filtered.push(obj);
      }
    });
  });

  return filtered;
}

console.log(filterUsers(users, "Su"));

[編輯]

我對對象上任何字段的結構、名稱或數量不做任何假設，因此我不想使用諸如object.field_name === 'something'類object.field_name === 'something' 。

Answer 1

您可以過濾並使用_.some()來迭代值，並使用Array.includes() （或 lodash 等效項）檢查值中是否存在該術語。

 const filterUsers = (collection, term) => collection.filter(o => _.some(o, v => v.includes(term))); const users = [{"first_name":"Super","last_name":"User"},{"first_name":"Admin","last_name":"Istrator"}]; console.log(filterUsers(users, "Su"));

 <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.15/lodash.js"></script>

同樣的想法使用lodash/fp ：

 const { filter, some, includes } = _; const filterUsers = term => filter(some(includes(term))); const users = [{"first_name":"Super","last_name":"User"},{"first_name":"Admin","last_name":"Istrator"}]; console.log(filterUsers("Su")(users));

 <script src='https://cdn.jsdelivr.net/g/lodash@4(lodash.min.js+lodash.fp.min.js)'></script>

Answer 2

沒有第三方庫的解決方案可能是：

var term = 'Su';
var filtered = users.filter(({first_name, last_name}) => {
 return (first_name.includes(term) || last_name.includes(term));
});

console.log(filtered);

希望對您有所幫助。