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我如何使用 adonis/node.js 在 leftJoin 中區分?

[英]How i can make a distinct in leftJoin using adonis/node.js?

我試圖在 leftJoin 中區分,但.distinct()似乎不適用於我的上下文。

我有這個查詢:

const questions = Database
                                .query()
                                .select('book_unit_question.*')
                                .select('book_unit.unit')
                                .select('book_unit.sequence')
                                .select('books.id as book_id')
                                .select('book_unit_question_option.description as correct_answer_description_id')
                                .select('users.username')
                                .from('book_unit_question')
                                .leftJoin('book_unit_question_option', 'book_unit_question.id', 'book_unit_question_option.book_unit_question_id')
                                .distinct('book_unit_question.id')
                                .innerJoin('book_unit', 'book_unit.id', 'book_unit_question.book_unit_id')
                                .innerJoin('books', 'books.id', 'book_unit.book_id')
                                .innerJoin('users', 'book_unit_question.user_id', 'users.id')
                                .where('books.id', '=', request.params.id)

但是當我得到結果時,我重復了book_unit_question.id

0: {id: 11, book_unit_id: 2, question_form: "Texto", option_form: "Texto",…}
1: {id: 11, book_unit_id: 2, question_form: "Texto", option_form: "Texto",…}
2: {id: 11, book_unit_id: 2, question_form: "Texto", option_form: "Texto",…}
3: {id: 12, book_unit_id: 2, question_form: "Texto", option_form: "Texto", type_answer: "Aberta",…}

我只需要:

0: {id: 11, book_unit_id: 2, question_form: "Texto", option_form: "Texto",…}
1: {id: 12, book_unit_id: 2, question_form: "Texto", option_form: "Texto", type_answer: "Aberta",…}

嘗試使用不帶參數的distinct()

const questions = Database
  .from('book_unit_question')
  .select('book_unit_question.*', 'book_unit.unit', 'book_unit.sequence', 'books.id as book_id', 'book_unit_question_option.description as correct_answer_description_id', 'users.username')
  .distinct()
  .leftJoin('book_unit_question', 'book_unit_question.id', '=', 'book_unit_question_option.book_unit_question_id')
  .join('book_unit', 'book_unit.id', '=', 'book_unit_question.book_unit_id')
  .join('books', '=', 'books.id', 'book_unit.book_id')
  .join('users', '=', 'book_unit_question.user_id', 'users.id')
  .where('books.id', '=', request.params.id);

文檔在這里

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