為什么以下代碼顯示錯誤？

Question

每當我運行以下代碼時，它將引發錯誤。

from sys import argv
 script, first, second, third = argv 
 print "The script is called:", scrip
 print "Your first variable is:", first
 print "Your second variable is:", second
 print "Your third variable is:", third

錯誤出現-

File "/Users/rishabh/Documents/rishabh.py", line 3
    script, first, second, third ,fourth= argv 
    ^
IndentationError: unexpected indent

Answer 1

解：

from sys import argv
script, first, second, third = argv 
print "The script is called:", scrip
print "Your first variable is:", first
print "Your second variable is:", second
print "Your third variable is:", third

只需復制並運行。 它應該工作：p

Answer 2

正如丹尼爾（Daniel）所說：“因為您已經縮進了，所以不應該嗎？”

Python對縮進很敏感。 每個縮進都必須是相同數量的單位，無論是單個縮進還是兩個空格縮進，甚至是（如果需要）30個制表符！

在您的代碼中，每條打印語句行上都有一個（最可能）偶然的空間。 因為它們不需要縮進（如果它們在if語句中，或者它們會進行某種排序），則if會引發錯誤。 解釋器根本無法理解為什么要縮進。

正確的代碼（空格已刪除）：

from sys import argv
script, first, second, third = argv 
print "The script is called:", scrip
print "Your first variable is:", first
print "Your second variable is:", second
print "Your third variable is:", third

Answer 3

“腳本”一詞前有一個空格（縮進）。