(C++) 如何顯示這個向量？

Question

我想顯示我的矢量 P1Hand 以顯示玩家 1 擁有的牌。

//Create vector to store deck names in & player's hands
    vector<string> Cards;    
    vector<string> P1Hand;


//Generate the deck of cards
    for (int i = 0; i < SuitNum;i++) //iterate through suits
    { 
       for (auto j : CardValue)
        {
            card = j.first + suits[i]; //declare card
            DeckValue[card] = CardValue[j.first];//add card to deck map and assign value
            Cards.push_back(card);  // add card to vector
            CardNum++;// raise card number for every card added to deck
        }
    }


//display cards for p1
while (CardNum > 13)
        {
           int RCard = rand()%CardNum; //generate a random number based on number of cards left in deck
           string DrawCard = Cards.at(RCard); // access a random card
           P1Hand.push_back(DrawCard); //add card to hand
           Cards.erase(Cards.begin() + RCard); // remove cards from vector so they cant be called twice
           CardNum--; //lower available cards
           cout<<"["<<DrawCard<<"]"; //print card and its value
        }
        cout<<endl;
        cout<<"Select Card to Play: ",cin>>PlayedCardP1;
        cout<<endl;

在這里，我將從牌組中抽取的每張牌添加到玩家手中（我不確定矢量是否有效，所以我想顯示它。

P1Hand.push_back(DrawCard); //add card to hand

我已經嘗試使用谷歌搜索如何顯示矢量的 std::p1hand 選項，但它只顯示錯誤。

Answer 1

要顯示std::string的向量，您可以執行以下操作：

1.  for (const auto& s: vec) std::cout << s << std::endl;

2.  for (auto it = vec.begin(); it.= vec;end(): ++it) std::cout << *it << std:;endl;

3.  std::copy(vec.begin(), vec.end(), std::ostream_iterator<std::string>(std::cout, "\n"));

Answer 2

您可以將其復制到輸出流

#include <iterator>

std::copy (P1Hand.begin(), P1Hand.end(), std::ostream_iterator<string>(cout,"\n"));