如何找到工資最高的前 2 個不同員工姓名？

Question

這是我的桌子

select emp_no, salary
from salaries
order by salary desc

emp_no, salary
'43624', '158220'
'43624', '157821'
'47978', '155709'
'109334', '155377'
'109334', '155190'
'109334', '154888'
'109334', '154885'
'80823', '154459'
'43624', '153458'
'43624', '153166'
'47978', '151929'
'80823', '151768'
'109334', '151484'
'43624', '151115'
'46439', '150345'

我用過查詢

select distinct emp_no, salary
from salaries
order by salary desc
limit 2

但它只返回同一用戶的前兩名工資**我需要前兩名最高員工 emp_no 的 emp_no 和他們的工資 **

Answer 1

您可以使用subquery和max()聚合函數。

select * from 
    (select emp_no, max(salary) maxsalary from salaries group by emp_no) t1 
order by t1.maxsalary desc
limit 2

Answer 2

我認為這里不需要子查詢。 您可以直接聚合和排序：

select emp_no, max(salary) max_salary 
from salaries 
group by emp_no 
order by max_salary desc
limit 2