[英]How to display data in input from selecting option in drop down with database MYSQL?
在數據庫中選擇項目后,我在輸入中顯示數據時遇到問題。 因為我使用動態行。 我從第一行選擇數據,數據顯示在第一行輸入文本上。 然后我添加一個新行,並從第二行中選擇數據。 和數據顯示在第一行輸入文本上,而不是第二行?
這是我的HTML
<table class="table-bordered table item" id="t1">
<thead>
<tr>
<th width="35%" class="text-center">Nama Barang</th>
<th width="19%"class="text-center">Harga</th>
<th width="12%" class="text-center">Qty</th>
<th width="14%" class="text-center">Satuan</th>
<th width="20%" class="text-center">Total Harga</th>
<th><button type="button" class="btn btn-success btn-sm addRow">+</button></th>
</tr>
</thead>
<tbody>
<tr class="item">
<td>
<select onchange="changeValue(this.value)" class="selectReason" id="reason" name="reasontxt[]" required>
<option value="" selected="" disabled="">-- Silahkan Pilih --</option>
<optgroup label="Nama Bahan Baku">
<?php
$query = mysqli_query($koneksi, "select * from bahan a, kategori_bahan b, satuan c WHERE a.id_kategori_bahan=b.id_kategori_bahan and a.id_satuan = c.id_satuan order by nm_bahan asc");
$result = mysqli_query($koneksi, "select * from bahan a, kategori_bahan b, satuan c WHERE a.id_kategori_bahan=b.id_kategori_bahan and a.id_satuan=c.id_satuan order by nm_bahan asc");
$jsArray = "var prdName = new Array();\n";
while ($row = mysqli_fetch_array($result)) {
echo '<option value="' . $row['nm_bahan'] . '">' . $row['nm_bahan'] . '</option>';
$jsArray .= "prdName['" . $row['nm_bahan'] . "'] = {id_satuan:'" . addslashes($row['nm_satuan']) . "',harga:'".addslashes($row['harga'])."'};\n";
}
?>
</optgroup>
</select>
</td>
<td>
<input type="text" name="harga[]" placeholder="Harga" id="harga" class="form-control price amount" onkeypress="return hanyaAngka(event)" autocomplete="off" required />
</td>
<td>
<input type="text" name="qty[]" placeholder="Qty" class="form-control qnty amount" value="0" onkeypress="return hanyaAngka(event)" autocomplete="off" required />
</td>
<td>
<input type="text" name="satuan[]" placeholder="Satuan" id="id_satuan" class="form-control" onkeypress="return hanyaAngka(event)" readonly>
</td>
<td>
<input type="text" name="harga_total[]" placeholder="Total Harga" class="form-control totalharga" onkeypress="return hanyaAngka(event)" autocomplete="off" readonly />
</td>
</tr>
</tbody>
</table>
這是我的jQUERY和JavaScript
<script type="text/javascript">
<?php echo $jsArray; ?>
function changeValue(id){
document.getElementById('harga').value = prdName[id].harga;
document.getElementById('id_satuan').value = prdName[id].id_satuan;
};
window.onload=function(){
$(document).ready(function () {
var r = 1;
$('.addRow').click(function () {
r++;
$('#t1').append('<tr id="row' + r + '" class="item"><td><select onchange="changeValue(this.value)" class="selectReason" id="reason" name="reasontxt[]" required><option value="" selected="" disabled="">-- Silahkan Pilih --</option><optgroup label="Nama Bahan Baku"><?php $query=mysqli_query($koneksi, "select * from bahan a, kategori_bahan b, satuan c WHERE a.id_kategori_bahan=b.id_kategori_bahan and a.id_satuan=c.id_satuan order by nm_bahan asc"); $result = mysqli_query($koneksi, "select * from bahan a, kategori_bahan b, satuan c WHERE a.id_kategori_bahan=b.id_kategori_bahan and a.id_satuan=c.id_satuan order by nm_bahan asc"); $jsArray = "var prdName = new Array();\n";while ($row = mysqli_fetch_array($result)) { echo '<option value="' . $row['nm_bahan'] . '">' . $row['nm_bahan'] . '</option>'; $jsArray .= "prdName['" . $row['nm_bahan'] . "'] = {id_satuan:'" . addslashes($row['nm_satuan']) . "',harga:'".addslashes($row['harga'])."'};\n";}?></optgroup></select></td><td><input type="text" name="harga[]" placeholder="Harga" id="harga" class="form-control price amount" onkeypress="return hanyaAngka(event)" autocomplete="off" required /></td><td><input type="text" name="qty[]" placeholder="Qty" class="form-control qnty amount" value="0" onkeypress="return hanyaAngka(event)" autocomplete="off" required /></td><td><input type="text" name="satuan[]" placeholder="Satuan" id="id_satuan" class="form-control" onkeypress="return hanyaAngka(event)" readonly/></td><td><input type="text" name="harga_total[]" placeholder="Total Harga" class="form-control totalharga" onkeypress="return hanyaAngka(event)" autocomplete="off" readonly /></td><td><button type="button" name="remove" id="' + r + '" class="btn btn-danger btn-sm btn_remove">x</button></td></tr>');
$(".selectReason").select2({dropdownParent: $('#TambahData .modal-content'),width:'100%'});
});
$(document).on('click', '.btn_remove', function () {
var button_id = $(this).attr("id");
$('#row' + button_id + '').remove();
calcAll();
});
$(document).on("keyup", ".amount", calcAll);
});
function calcAll() {
$(".item").each(function () {
var qnty = 0;
var price = 0;
var totalharga = 0;
var diskon = 0;
var uangmuka = 0;
if (!isNaN(parseInt($(this).find(".qnty").val()))) {
qnty = parseInt($(this).find(".qnty").val());
}
if (!isNaN(parseInt($(this).find(".price").val()))) {
price = parseInt($(this).find(".price").val());
}
if (!isNaN(parseInt($(this).find(".uangmuka").val()))) {
uangmuka = parseInt($(this).find(".uangmuka").val());
}
if (!isNaN(parseInt($(this).find(".diskon").val()))) {
diskon = parseInt($(this).find(".diskon").val());
}
totalharga = qnty * price;
$(this).find(".totalharga").val(totalharga.toFixed());
});
var sum = 0;
$(".totalharga").each(function () {
if (!isNaN(this.value) && this.value.length != 0) {
sum += parseInt(this.value);
}
});
$("#subtotal").val(sum.toFixed());
var diskon = 0;
if (!isNaN(parseInt($("#diskon").val()))) {
diskon = parseInt($("#diskon").val());
}
var total = 0;
if (!isNaN(parseInt($("#total").val()))) {
total = parseInt($("#total").val());
}
total = sum - (sum*(diskon/100));
$("#total").val(total.toFixed());
}
}
</script>
似乎是選擇器的問題(在這種情況下為 ID)。 如果我正確理解您的情況,在添加一行然后選擇“Nama Barang”時,您希望“Harga”列填充與所選下拉值關聯的“harga”值,對嗎?
添加行時,每個輸入的 ID 都與前一行的輸入相同。 因此,在調用 changevalue() 函數時,javascript 將選擇 ID 為“harga”的第一個元素。 因此,您將始終更新第一行。 當心<tr id="row"
它也會給你帶來麻煩。
首先,您應該使用class="harga"
而不是id="harga"
。
然后您可以使用以下內容修改您的腳本:
在選擇: onchange="changeValue(this)"
和在 javascript 中:
function changeValue(select){
var id = select.value;
var row = $(select).closest(".item");
row.find(".harga").value = prdName[id].harga;
row.find(".id_satuan").value = prdName[id].id_satuan;
}
我在此處使用建議的更改簡化了您的代碼。 請記住,此代碼未優化,仍然存在冗余和錯誤做法(內聯樣式、重復代碼、未優化的 mysql 查詢),並且尚未經過測試。 希望這可以幫助。
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