T-SQL 查詢匯總每年每月的總數，以及迄今為止的累計金額

Question

我有一個捕獲每個銷售交易的數據庫表：

Transactions 
(
    ID INT, 
    TransactionDate DATETIME, 
    SalesAmount MONEY
)

我想編寫一個返回報告的T-SQL查詢（下面的快照示例）。 第一列列出月份，下一列列出一年內每月的總銷售額，最后一列該年截至本月的累計金額。 僅適用於 2018 年。

任何想法或解決方案？ 謝謝你。

Answer 1

嘗試這個：

;with cte as
( 
   Select 
   YEAR(TransactionDate) as [Year],
   MONTH(TransactionDate) as [Month],  
   SUM (SalesAmount) as [MonthlySales], 
   DATEPART(m, TransactionDate) as [MonthNumber] 
   from Transactions 
   group by YEAR(TransactionDate), MONTH(TransactionDate)
) 
select 
a.[Month], a.MonthlySales as [MonthlySales 2018], SUM(b.MonthlySales) as [Cumulative 2018]
from cte a inner join cte b on a.MonthNumber  >= b.MonthNumber 
WHERE (a.[Year]) = 2018   AND  (b.[Year]) = 2018  
group by a.[Month], a.MonthlySales
ORDER by a.[Month]

Answer 2

試試這個：

With Q 
as
(
   Select DatePart(yyyy,TransactionDate) 'Year',DatePart(m,TransactionDate) 'Month',  sum(SalesAmount) 'Sales'
   From Transactions 
   Group by DatePart(yyyy,TransactionDate),DatePart(m,TransactionDate)
) 
Select q.Year,q.Month,( Select sum(q1.Sales)
                                From Q q1
                                Where q1.Year=q.Year
                                    And  q1.Month <= q.Month
                                ) 'Cumulative Sale'
From Q q
Order by q.Year,q.Month

Answer 3

您將使用聚合和窗口函數：

select datename(month, transaction_date) as mon,
       sum(salesAmount) as monthly_sales,
       sum(salesAumount) over (order by min(transaction_date)) as running_amount
from transactions t
where t.transaction_date >= '2018-01-01' and
      t.transaction_date < '2019-01-01'
group by datename(month, transaction_date)
order by min(transaction_date);