[英]Android Error: Value <br of type java.lang.String cannot be converted to JSONObject
目前,我創建了一個具有登錄功能的應用程序。 為了從 android 連接到 MySQL 數據庫,我使用 PHP。 當我使用 MySQLi 時,一切正常。 但是當我轉換為 PDO 時,錯誤將與我的問題標題相同。 誰能知道是什么問題? 下面是我的PHP代碼:
<?php
require_once 'configPDO.php';
$response = array();
if(isTheseParametersAvailable(array('badgeid', 'pwd'))){
$badgeid = $_POST['badgeid'];
$pwd = $_POST['pwd'];
$stmt = $conn->prepare("SELECT badgeid, email, fullname, roles_id, team_id FROM users WHERE badgeid = :badgeid AND pwd = :pwd AND roles_id = 3");
// $stmt->bind_param("ss",$badgeid, $pwd);
$stmt->bindParam(':badgeid',$badgeid,PDO::PARAM_STR);
$stmt->bindParam(':pwd',$pwd,PDO::PARAM_STR);
$stmt->execute();
//$stmt->store_result();
if($stmt->rowCount() > 0){
$stmt->bindParam($badgeid, $email, $fullname, $roles_id, $team_id);
$stmt->fetch();
$user = array(
'badgeid'=>$badgeid,
'email'=>$email,
'fullname'=>$fullname,
'roles_id'=>$roles_id,
'team_id'=>$team_id
);
$response['error'] = false;
$response['message'] = 'Login successfull';
$response['user'] = $user;
}else{
$response['error'] = false;
$response['message'] = 'Invalid username or password';
}
}
echo json_encode($response);
function isTheseParametersAvailable($params){
foreach($params as $param){
if(!isset($_POST[$param])){
return false;
}
}
return true;
}
你的第二個bindParam()
(你應該閱讀並理解這個方法到底是做什么的!)在if
條件中是無稽之談!
改變這個:
if($stmt->rowCount() > 0){
$stmt->bindParam($badgeid, $email, $fullname, $roles_id, $team_id);
$stmt->fetch();
$user = array(
'badgeid'=>$badgeid,
'email'=>$email,
'fullname'=>$fullname,
'roles_id'=>$roles_id,
'team_id'=>$team_id
);
對此:
$result = $stmt->fetch(\PDO::FETCH_ASSOC); // Get results as array
if ($result) {
// Since we only get the fields we want to send back, you can assign `$result` directly to `$response['user']`
$response['user'] = $result;
PHP 拋出了一個相關的錯誤,您會在請求的原始響應中看到它!
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