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[英]Remove elements in a list if difference with previous element less than value
[英]How to sum the elements of a list if the difference of elements in another list is less than a certain value
鑒於兩個列表具有相同的大小。 我想首先計算一個列表中連續元素之間的差異,然后如果差異滿足條件,則對第二個列表中的相應元素求和。
例如:
List_1 = [0.1, 0.2, 0.3, 0.5, 0.6, 0.9]
List_2 = [1, 1, 1, 1, 1, 1]
我要總結在相應的元件List_2
如果在連續元素之間的差List_1
小於或等於0.1。 如果差值大於 0.1,則什么都不做。 在這種情況下, List_1
的差異是[0.1, 0.1, 0.2, 0.1, 0.3]
那么我預期的總和列表是[ 3, 2, 1]
。
以下代碼本質上使用 切片和 Python 的內置函數zip
為for
循環提供合適的可迭代對象。 我嘗試添加一些解釋性調用來print
以顯示發生了什么:
# Your list input
X = [0.1, 0.2, 0.3, 0.5, 0.6, 0.9]
Y = [1, 2, 4, 8, 16, 32]
# Calculate sums
Z = [Y[0]]
for x_1, x_2, y in zip(X, X[1:], Y[1:]):
print(f"Z currently looks like this: {Z}")
print(f"Is {x_1} to {x_2} leq 0.1? {x_2 - x_1 <= 0.1}", end=" ")
if x_2 - x_1 <= 0.1:
print(f"=> Add {y} to last sum in Z")
Z[-1] += y
else:
print(f"=> Use {y} to start a new sum in Z")
Z += [y]
print("Final result:", Z)
將打印:
Z currently looks like this: [1]
Is 0.1 to 0.2 leq 0.1? True => Add 2 to last sum in Z
Z currently looks like this: [3]
Is 0.2 to 0.3 leq 0.1? True => Add 4 to last sum in Z
Z currently looks like this: [7]
Is 0.3 to 0.5 leq 0.1? False => Use 8 to start a new sum in Z
Z currently looks like this: [7, 8]
Is 0.5 to 0.6 leq 0.1? True => Add 16 to last sum in Z
Z currently looks like this: [7, 24]
Is 0.6 to 0.9 leq 0.1? False => Use 32 to start a new sum in Z
Final result: [7, 24, 32]
當然,您可以刪除所有對print
調用,代碼仍然可以工作。
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