JHipster：使用附加信息注冊用戶[幫助]

Question

我一直在按照本指南嘗試向用戶添加信息，一切都很順利，直到我到達將輸入字段添加到 register.component.html 的部分，當我添加 ngModel 指令時，頁面停止工作，密碼強度不再起作用，當我嘗試注冊用戶時，我注冊失敗並出現以下錯誤：

2019-12-10 16:31:18.875 ERROR 912 --- [ XNIO-1 task-14] o.h.engine.jdbc.spi.SqlExceptionHelper   : Column "USEREXTRA0_.USER_ID" not found; SQL statement`select userextra0_.user_id as user_id8_25_, userextra0_.activo as activo1_25_, userextra0_.cod_p as cod_p2_25_, userextra0_.morada as morada3_25_, userextra0_.nif as nif4_25_, userextra0_.nome as nome5_25_, userextra0_.permiss_change as permiss_6_25_, userextra0_.telef as telef7_25_, userextra0_.user_permissions_id as user_per9_25_, userextra0_.user_profile_id as user_pr10_25_ from user_extra userextra0_ [42122-200]`
2019-12-10 16:31:18.876 ERROR 912 --- [ XNIO-1 task-14] dw.aop.logging.LoggingAspect             : Exception in dw.web.rest.UserExtraResource.getAllUserExtras() with cause = 'org.hibernate.exception.SQLGrammarException: could not prepare statement' and exception = 'could not prepare statement; SQL [select userextra0_.user_id as user_id8_25_, userextra0_.activo as activo1_25_, userextra0_.cod_p as cod_p2_25_, userextra0_.morada as morada3_25_, userextra0_.nif as nif4_25_, userextra0_.nome as nome5_25_, userextra0_.permiss_change as permiss_6_25_, userextra0_.telef as telef7_25_, userextra0_.user_permissions_id as user_per9_25_, userextra0_.user_profile_id as user_pr10_25_ from user_extra userextra0_]; nested exception is org.hibernate.exception.SQLGrammarException: could not prepare statement'
2019-12-10 16:31:18.878 ERROR 912 --- [ XNIO-1 task-14] o.z.problem.spring.common.AdviceTraits   : Internal Server Error

當我嘗試查看我的 UserExtra 實體時，我收到內部服務器錯誤。

這是我的 UserExtra 表，我意識到 ID 字段應該被稱為 User_Id 但我按照指南做了一切，但不知道出了什么問題

Answer 1

我建議您檢查您的 Liquibase 腳本。 很可能該字段未在用戶額外表定義中定義。