Azure 自定義資源提供程序 - ARM 模板的自定義錯誤消息

Question

如果我的自定義資源提供程序想要向 ARM 返回自定義失敗消息，我的響應正文應該是什么？ 我有一個由 JavaScript Azure 函數支持的自定義資源提供程序，我嘗試了以下操作

 body = {
       error: {
            code: "Failed",
            message: "A custom error message'."
        }
    };
httpStatus = 200;

 context.res = {
            status: httpStatus,
            headers: {
                'Content-Type': 'application/json'
              },
            body: body
        };

ARM 模板部署失敗並出現錯誤 -

{
    "error": {
        "code": "ResourceDeploymentFailure",
        "message": "The response for resource had empty or invalid content."
    }

我也試過

 body = {
       properties: {
       provisioningState: "Failed",
       error: {
            code: "Failed",
            message: "A custom error message'."
        }
       }
    };
httpStatus = 200;

 context.res = {
            status: httpStatus,
            headers: {
                'Content-Type': 'application/json'
              },
            body: body
        };

ARM 模板部署失敗並出現錯誤

"The resource operation completed with terminal provisioning state 'Failed"

我希望 ARM 模板部署失敗並顯示我從 Azure 函數返回的自定義錯誤消息 - “自定義錯誤消息”。

編輯：

這是我的 ARM 模板

{
  "$schema": "https://schema.management.azure.com/schemas/2015-01-01/deploymentTemplate.json#",
  "contentVersion": "1.0.0.0",
  "parameters": {
    "resourcePrefix": {
      "type": "string",
      "defaultValue": "prfx-",
      "maxLength": 6,
      "metadata": {
        "description": "The prefix of HLF resource."
      }
    },
    "randomGuid": {
      "defaultValue": "[newGuid()]",
      "type": "string",
      "metadata": {
        "description": "New random GUID"
      }
    }
  },
  "variables": {
    "funcName": "[concat(parameters('resourcePrefix'), substring(parameters('randomGuid'), 0, 5))]",
    "myResourceProvider": "my-custom-provider",
    "location": "[resourceGroup().location]"
  },
  "resources": [
    {
      "apiVersion": "2018-09-01-preview",
      "type": "Microsoft.CustomProviders/resourceProviders",
      "name": "[variables('myResourceProvider')]",
      "location": "[variables('location')]",
      "properties": {
        "resourceTypes": [
          {
            "name": "deploy",
            "routingType": "Proxy",
            "endpoint": "<azure-func-url>"
          }
        ]
      }
    },
    {
      "apiVersion": "2018-09-01-preview",
      "type": "Microsoft.CustomProviders/resourceProviders/deploy",
      "name": "[concat(variables('myResourceProvider'), '/', variables('funcName'))]",
      "location": "[variables('location')]",
      "dependsOn": [
        "[concat('Microsoft.CustomProviders/resourceProviders/',variables('myResourceProvider'))]"
        ]      
    }
  ],
  "outputs": {
  }
}

Answer 1

自定義提供程序當前不支持按原樣代理錯誤消息。 自定義錯誤消息將作為詳細信息嵌套在標准消息下。

但是，看起來有一個錯誤正在阻止錯誤通過 ARM 模板傳播。 這應該很快修復！

Answer 2

@jjbfour 是對的。 自定義消息嵌套在傳播的消息中的“下游”標簽下。 但這對我來說很好。 以下作品

 body = {
       error: {
            code: "Failed",
            message: "A custom error message'."
        }
    };
httpStatus = 400;

 context.res = {
            status: httpStatus,
            headers: {
                'Content-Type': 'application/json'
              },
            body: body
        };

我之前犯的錯誤是沒有正確設置 HTTP 狀態。