JUnit 5 測試

Question

我如何使用 java 和 @test 注釋通過 junit 測試用例實現對此類中的 3 個方法的完整分支覆蓋。

public class StringStack {
private int capacity = 10;
private int pointer = 0;
private String[] objects = new String[capacity];

public void push(String o) {
    if (pointer >= capacity)
        throw new IllegalArgumentException("Stack exceeded capacity!");
    objects[pointer++] = o;

}
public String pop() {
    if (pointer <= 0)
        throw new IllegalArgumentException("Stack empty");
    return objects[--pointer];

}

public boolean isEmpty() {
    return pointer <= 0;

}

我已經編寫了以下測試用例，並且我已經為 isEmpty() 方法實現了這一點，盡管我正在努力為其他兩種方法編寫測試用例，因為它們都返回對象指針，而我不知道如何在我的測試文件中對其進行初始化.

class squareTest {

    //1.
    @Test 
    public void push() {

        StringStack push1 = new StringStack();
        String e2 = push1.pop();
        try {
            Assert.fail( "Should have thrown an exception" );
        assertEquals(IllegalArgumentException("Stack empty"), e2);
        //java.lang.IllegalArgumentException: Stack empty

        }catch (Exception e) {
            String expmessage = "I should get this message";


        }




    }

    @Test
    public void testTC3()
    {
        try {
            StringStack.push(o);
            fail(); // if we got here, no exception was thrown, which is bad
        } 
        catch (Exception e) {
            final String expected = "Legal Values: Package Type must be P or R";
            assertEquals( expected, e.getMessage());
        }        
    }

    //3.EMPTY TEST CASES
    @Test
    public void empty()
    {
        StringStack test2 = new StringStack();
        boolean e1 = test2.isEmpty();
        assertEquals(true, e1);
    } 
    @Test
    public void notEmpty()
    {
        StringStack test3 = new StringStack();
        boolean ne1 = test3.equals("im not empty");
        assertEquals(false, ne1);
    }
}

Answer 1

我會給你一個第一個函數的例子

public void push(String o) {
    if (pointer >= capacity)
        throw new IllegalArgumentException("Stack exceeded capacity!");
    objects[pointer++] = o;
}

你需要 3 個統一測試來完全覆蓋這個

1. 對於指針 == 容量
2. 一個用於指針 > 容量
3. 最后一個指針<容量

對於分支覆蓋，您只需要 1 和 3 或 2 和 3，盡管我建議所有三個都用於關鍵功能。

Answer 2

也許低於測試同時有助於獲得全面覆蓋。

推法測試

• 指針 >= 容量

  @Test(exception = IllegalArgumentException.class) public void push_PointerGreaterThanCapacity_ExceptionThrow(){ WhiteBox.setInternalState(yourObject, "pointer",11); String inputString = "Hello"; yourObject.push(inputString); }

• 指針<容量

  @Test public void push_PointerSmallerThanCapacity_ExceptionThrow(){ String inputString = "Hello"; yourObject.push(inputString); int pointer = WhiteBox.getInternalState(yourObject,"pointer"); String[] objects = WhiteBox.getInternalState(yourObject,"objects"); assertEquals(inputString, objects[pointer-1]); }

流行方法測試

• 指針 < 0

   @Test(exception = IllegalArgumentException.class) public void pop_PointerNegative_ExceptionThrow(){ WhiteBox.setInternalState(yourObject, "pointer",-1); String inputString = "Hello"; yourObject.push(inputString); }

• 指針 > 0

   @Test public void pop_pointerGreaterThenZero_PopValue(){ //set pointer WhiteBox.setInternalState(yourObject, "pointer",2); String[] stringList = {"String0","String1","String2"}; //object array WhiteBox.setInternalState(yourObject, "objects",stringList); String actualOutput = yourObject.pop(); assertEquals(actualOutput, stringList[1]); }

在這里， yourObject 是您測試的類的對象。