如何在 anaconda 上解決 Jupyter 中的這個內核錯誤

Question

我試圖從 jupyter 打開筆記本，但我收到以下消息。 有誰知道如何解決這個問題？ 僅供參考，我已經在 Windows 10 上安裝了 anaconda3 64 位。

提前致謝。

    Traceback (most recent call last):
  File "C:\Anaconda3\lib\site-packages\tornado\web.py", line 1699, in _execute
    result = await result
  File "C:\Anaconda3\lib\site-packages\tornado\gen.py", line 742, in run
    yielded = self.gen.throw(*exc_info)  # type: ignore
  File "C:\Anaconda3\lib\site-packages\notebook\services\sessions\handlers.py", line 72, in post
    type=mtype))
  File "C:\Anaconda3\lib\site-packages\tornado\gen.py", line 735, in run
    value = future.result()
  File "C:\Anaconda3\lib\site-packages\tornado\gen.py", line 742, in run
    yielded = self.gen.throw(*exc_info)  # type: ignore
  File "C:\Anaconda3\lib\site-packages\notebook\services\sessions\sessionmanager.py", line 88, in create_session
    kernel_id = yield self.start_kernel_for_session(session_id, path, name, type, kernel_name)
  File "C:\Anaconda3\lib\site-packages\tornado\gen.py", line 735, in run
    value = future.result()
  File "C:\Anaconda3\lib\site-packages\tornado\gen.py", line 742, in run
    yielded = self.gen.throw(*exc_info)  # type: ignore
  File "C:\Anaconda3\lib\site-packages\notebook\services\sessions\sessionmanager.py", line 101, in start_kernel_for_session
    self.kernel_manager.start_kernel(path=kernel_path, kernel_name=kernel_name)
  File "C:\Anaconda3\lib\site-packages\tornado\gen.py", line 735, in run
    value = future.result()
  File "C:\Anaconda3\lib\site-packages\tornado\gen.py", line 209, in wrapper
    yielded = next(result)
  File "C:\Anaconda3\lib\site-packages\notebook\services\kernels\kernelmanager.py", line 168, in start_kernel
    super(MappingKernelManager, self).start_kernel(**kwargs)
  File "C:\Anaconda3\lib\site-packages\jupyter_client\multikernelmanager.py", line 110, in start_kernel
    km.start_kernel(**kwargs)
  File "C:\Anaconda3\lib\site-packages\jupyter_client\manager.py", line 240, in start_kernel
    self.write_connection_file()
  File "C:\Anaconda3\lib\site-packages\jupyter_client\connect.py", line 547, in write_connection_file
    kernel_name=self.kernel_name
  File "C:\Anaconda3\lib\site-packages\jupyter_client\connect.py", line 212, in write_connection_file
    with secure_write(fname) as f:
  File "C:\Anaconda3\lib\contextlib.py", line 112, in __enter__
    return next(self.gen)
  File "C:\Anaconda3\lib\site-packages\jupyter_client\connect.py", line 102, in secure_write
    with os.fdopen(os.open(fname, open_flag, 0o600), mode) as f:
PermissionError: [Errno 13] Permission denied: 'C:\\Users\\K\\AppData\\Roaming\\jupyter\\runtime\\kernel-4a355bda-9e3b-4ec8-af5c-f28225b6efa3.json'

Answer 1

請通過創建新的 conda 環境進行嘗試。 使用以下命令創建 conda 環境：

conda create -n <env_name> -c intel python=3.6

使用以下命令激活環境：

source activate <env_name>

請在此環境中安裝所需的軟件包。 請使用以下命令安裝 ipykernal：

conda install ipykernel
ipython kernel install --name <env_name> --user 

從 jupyter notebook 中選擇已安裝的 ipykernal。 請參考此鏈接： https://github.com/jupyter/notebook/issues/2301 : https://github.com/jupyter/notebook/issues/2301