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[英]Why does my matplotlib bar diagram change when I am running the same python code but in a for-loop
[英]When running this code, why does the loop not wait for my response?
import random
def rock_paper_scissors(choice):
computer_choice = random.choice(['rock', 'paper', 'scissors'])
while True:
if choice == computer_choice:
print("Tie! Play again.")
choice
elif choice.lower() == 'quit':
break
elif choice.lower() == 'rock' and computer_choice.lower() == 'paper':
print("TRY AGAIN!", computer_choice.lower(), "beats", choice.lower())
choice
elif choice.lower() == 'rock' and computer_choice.lower() == 'scissors':
print("YOU WON!", choice.lower(), "beats", computer_choice.lower())
choice
elif choice.lower() == 'paper' and computer_choice.lower() == 'scissors':
print("TRY AGAIN!", computer_choice.lower(), "beats", choice.lower())
choice
elif choice.lower() == 'paper' and computer_choice.lower() == 'rock':
print("YOU WON!", choice.lower(), "beats", computer_choice.lower())
choice
elif choice.lower() == 'scissors' and computer_choice.lower() == "rock":
print("TRY AGAIN!", computer_choice.lower(), "beats", choice.lower())
choice
elif choice.lower() == 'scissors' and computer_choice.lower() == "paper":
print("YOU WON!", choice.lower(), 'beats', computer_choice.lower())
choice
else:
print("Sorry, invalid.")
choice
print(rock_paper_scissors(input("Rock paper or scissors (enter 'q' to quit): ")))
運行此代碼時,elif 中打印的任何內容都會在運行框中一遍又一遍地重復。 我不知道我是否應該修復 while 語句或在 elif 語句中添加額外的代碼。 輸入工作正常,但我不知道要向 while 循環添加什么。 (我是初學者 Python 程序員)
輸入語句不在while循環的范圍內,所以只調用一次。
一旦進入 while 循環,就不會改變選擇變量,因此會一遍又一遍地觸發相同的打印語句。
將輸入語句與計算機選擇初始化(這樣計算機每次都可以選擇一個新選項)一起移動到 while 循環中可以解決您的問題。
import random
def rock_paper_scissors():
while True:
computer_choice = random.choice(['rock', 'paper', 'scissors'])
choice = input("Rock paper or scissors (enter 'q' to quit): ")
if choice == computer_choice:
print("Tie! Play again.")
elif choice.lower() == 'quit':
break
elif choice.lower() == 'rock' and computer_choice.lower() == 'paper':
print("TRY AGAIN!", computer_choice.lower(), "beats", choice.lower())
elif choice.lower() == 'rock' and computer_choice.lower() == 'scissors':
print("YOU WON!", choice.lower(), "beats", computer_choice.lower())
elif choice.lower() == 'paper' and computer_choice.lower() == 'scissors':
print("TRY AGAIN!", computer_choice.lower(), "beats", choice.lower())
elif choice.lower() == 'paper' and computer_choice.lower() == 'rock':
print("YOU WON!", choice.lower(), "beats", computer_choice.lower())
elif choice.lower() == 'scissors' and computer_choice.lower() == "rock":
print("TRY AGAIN!", computer_choice.lower(), "beats", choice.lower())
elif choice.lower() == 'scissors' and computer_choice.lower() == "paper":
print("YOU WON!", choice.lower(), 'beats', computer_choice.lower())
else:
print("Sorry, invalid.")
rock_paper_scissors()
我想我會分享另一種寫作方式,這可能對初學者有所幫助。 目標是:
print("You Lose")
而不是三個。import random
def did_player_win(computer, player):
# Returns None for a tie, True for a win, False for a lose
if computer == player:
return None
if computer == 'paper':
return False if player == 'rock' else True
if computer == 'scissors':
return False if player == 'paper' else True
if computer == 'rock':
return False if player == 'scissors' else True
def play():
while True:
player = input("Rock, paper or scissors (enter 'q' to quit): ")
player = player.lower()
if player not in ['rock', 'paper', 'scissors']:
break
computer = random.choice(['rock', 'paper', 'scissors'])
player_won = did_player_win(computer, player)
if player_won is True:
print("YOU WON! {0} beats {1}".format(player, computer))
elif player_won is False:
print("TRY AGAIN! {0} beats {1}".format(computer, player))
else:
print("Tie! Both chose {0}".format(player))
play()
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