簡體   English   中英

在沒有 LoginRequiredMixin / django 的情況下向未登錄的用戶顯示登錄頁面

[英]Show a login page to a user who is not logged in without LoginRequiredMixin / django

這是我的代碼

class PostDetail(DetailView):
    model = Post

    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)
        context['form'] = CommentForm()
        return context

    def post(self, request, *args, **kwargs):
        form = CommentForm(request.POST)
        if request.user.is_authenticated:
            if form.is_valid():
                comment = form.save(commit=False)
                comment.comment_owner = request.user
                comment.post = Post.objects.get(pk=kwargs['pk'])
                comment.save()
                return redirect('blog:detail', pk=kwargs['pk'])
            else:
                return redirect('blog:detail', pk=kwargs['pk'])
        else:
             ???

我在詳細視圖中添加了評論表單
當未登錄的用戶嘗試添加評論時,我想顯示一個登錄頁面。
我沒有添加 LoginRequiredMixin 因為任何人都應該能夠看到這個帖子。
有什么建議嗎?

# You just need to redirect to login page

views.py

from django.shortcuts import render, redirect

class PostDetail(DetailView):
    model = Post

    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)
        context['form'] = CommentForm()
        return context

    def post(self, request, *args, **kwargs):
        form = CommentForm(request.POST)
        if request.user.is_authenticated:
            if form.is_valid():
                comment = form.save(commit=False)
                comment.comment_owner = request.user
                comment.post = Post.objects.get(pk=kwargs['pk'])
                comment.save()
                return redirect('blog:detail', pk=kwargs['pk'])
            else:
                return redirect('blog:detail', pk=kwargs['pk'])
        else:
             return redirect('login-user')


# add a namespace in your urls, so that the user can redirect to that namespace 'login-user'

urls.py

re_path(r'^login-admin/$', LoginView.as_view(), name='login-user'),

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM