在javascript中使用數字和特殊字符對字符串進行排序

Question

我正在嘗試使用數字和特殊字符組合對字符串進行排序。

但它給出了錯誤的命令。

<!DOCTYPE html>
<html>
<body>

<p>Click the button to sort the array.</p>

<button onclick="myFunction()">Try it</button>

<p id="demo"></p>

<script>
function MySort(alphabet)
{
    return function(a, b) {
        var index_a = alphabet.indexOf(a[0]),
        index_b = alphabet.indexOf(b[0]);

        if (index_a === index_b) {
            // same first character, sort regular
            if (a < b) {
                return -1;
            } else if (a > b) {
                return 1;
            }
            return 0;
        } else {
            return index_a - index_b;
        }
    }
}

function myFunction() {
  var items = ["AB_UI08","AB_UI03","AB_UI07","AB_UI04","AB_UI05","AB_UI014","AB_UI01","AB_UI09","AB_UI010","AB_UI011","AB_UI012","AB_UI013","AB_UI06","AB_UI016","AB_UI07","AB_UI018","AB_UI019","AB_UI015","AB_UI020","AB_UI02"

],
sorter = MySort('*!@_.()#^&%-=+01234567989abcdefghijklmnopqrstuvwxyz');

console.log(items.sort(sorter));
}
</script>

</body>
</html>

它給出了以下回應。 [“AB_UI01”、“AB_UI010”、“AB_UI011”、“AB_UI012”、“AB_UI013”、“AB_UI014”、“AB_UI015”、“AB_UI016”、“AB_UI017”、“AB_UI018”、“AB_UI010” AB_UI020”、“AB_UI03”、“AB_UI04”、“AB_UI05”、“AB_UI06”、“AB_UI07”、“AB_UI08”、“AB_UI09”]

未排序數組：["AB_UI08","AB_UI03","AB_UI07","AB_UI04","AB_UI05","AB_UI014","AB_UI01","AB_UI09","AB_UI010","AB_UI011","AB_UI012" ","AB_UI06","AB_UI016","AB_UI017","AB_UI018","AB_UI019","AB_UI015","AB_UI020","AB_UI02"]

預期輸出：[“AB_UI01”、“AB_UI02”、“AB_UI03”、“AB_UI04”、“AB_UI05”、“AB_UI06”、“AB_UI07”、“AB_UI08”、“AB_UI09”、“AB_UI010”、“AB_UI01012AB” ", "AB_UI013", "AB_UI014", "AB_UI015", "AB_UI016", "AB_UI17", "AB_UI018", "AB_UI019", "AB_UI020"]

感謝您的建議。

Answer 1

如果您喜歡按組排序，例如字母和/或數字，您可以使用String#localeCompare選項進行排序。

 var array = ["AB_UI08","AB_UI03","AB_UI07","AB_UI04","AB_UI05","AB_UI014","AB_UI01","AB_UI09","AB_UI010","AB_UI011","AB_UI012","AB_UI013","AB_UI06","AB_UI016","AB_UI07","AB_UI018","AB_UI019","AB_UI015","AB_UI020","AB_UI02"]; console.log(array.sort((a, b) => a.localeCompare(b, undefined, { numeric: true, sensitivity: 'base' })));

 .as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 2

鑒於您的單詞（例如AB_UI08 ）似乎類似於{letters}{digits} ，其中letters不是digits和[0-9]+形式的digits 。

即： letters==AB_UI和d==08 。

假設您想先按字母排序，然后按數字排序。

您可以將您的單詞映射到字母和數字，然后為了比較兩個單詞，如果它們的字母部分相等，則比較它們的數量。

 function toObj(w) { const letters = w.match(/^[^\\d]+/)[0] return { w, letters, d: parseInt(w.replace(letters,'')) } } const items = ["AB_UI08","AB_UI03","AB_UI07","AB_UI04","AB_UI05","AB_UI014","AB_UI01","AB_UI09","AB_UI010","AB_UI011","AB_UI012","AB_UI013","AB_UI06","AB_UI016","AB_UI07","AB_UI018","AB_UI019","AB_UI015","AB_UI020","AB_UI02"] const sorted = items.map(toObj).sort((a,b) => { const res = a.letters.localeCompare(b.letters) return res !== 0 ? res : ad - bd }).map(x => xw) console.log('sorted', sorted)

在javascript中使用數字和特殊字符對字符串進行排序

問題描述

2 個解決方案

解決方案1
1 已采納 2020-01-04 10:23:53

解決方案2
1 2020-01-04 11:18:51

在javascript中使用數字和特殊字符對字符串進行排序

問題描述

2 個解決方案

解決方案1 1 已采納 2020-01-04 10:23:53

解決方案2 1 2020-01-04 11:18:51

解決方案1
1 已采納 2020-01-04 10:23:53

解決方案2
1 2020-01-04 11:18:51