[英]How to Compare Selected Query Result in Oracle?
我有挑戰比較 2 個表agent_comm_summ_mh_new
和agent_comm_summ_mh_old
,新的將更新值。
這是查詢 1:
agent_name | participantid | old_net_payment | new_net_payment | sectionorder
leong | 10116 | 16729.3 | 17285.96 | 10
pwee | 10260 | 23128.69 | 23287.48 | 10
select xc.agentname, xc.participantid, bk.value as old_net_payment, xc.value as new_net_payment, xc.sectionorder
from agent_comm_summ_mh_new xc
inner join agent_comm_summ_mh_old bk on xc.participantid = bk.participantid and xc.buname = bk.buname
where xc.periodname = 'December 2019' and bk.value<>xc.value and xc.sectionorder=10 and bk.sectionorder=10;
這是查詢 2
agent_name | participantid | pi | subsectionoder
leong | 10116 | 556.66 | 15
pwee | 10260 | 158.79 | 15
select t.participantid, t.subsectionorder, t.agentname, t.value
from agent_comm_summ_mh_new t
where t.periodname = 'December 2019' and t.subsectionorder=15;
如何將兩個表的查詢寫入 1,我想要的結果如下:
agent_name | participantid | old_net_payment | new_net_payment | sectionorder | pi | subsectionorder
leong | 10116 | 16729.3 | 17285.96 | 10 | 556.66 | 15
pwee | 10260 | 23128.69 | 23287.48 | 10 | 158.79 | 15
您可以在表上使用自AGENT_COMM_SUMM_MH_NEW
: AGENT_COMM_SUMM_MH_NEW
如下:
SELECT
XC.AGENTNAME,
XC.PARTICIPANTID,
BK.VALUE AS OLD_NET_PAYMENT,
XC.VALUE AS NEW_NET_PAYMENT,
XC.SECTIONORDER,
T.SUBSECTIONORDER, -- ADDED THIS
T.VALUE AS PI -- ADDED THIS
FROM
AGENT_COMM_SUMM_MH_NEW XC
INNER JOIN AGENT_COMM_SUMM_MH_OLD BK ON XC.PARTICIPANTID = BK.PARTICIPANTID
AND XC.BUNAME = BK.BUNAME
-- SELF JOIN
INNER JOIN AGENT_COMM_SUMM_MH_NEW T ON XC.PARTICIPANTID = T.PARTICIPANTID
WHERE
XC.PERIODNAME = 'December 2019'
AND BK.VALUE <> XC.VALUE
AND XC.SECTIONORDER = 10
AND BK.SECTIONORDER = 10
AND T.PERIODNAME = 'December 2019' -- ADDED THIS
AND T.SUBSECTIONORDER = 15; -- ADDED THIS;
干杯!!
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.