對象數組上的過濾器數組包含 javascript

Question

我有一個這樣的數組：

let posts = [
  {title: "1", tags: ["funny", "good", "nice"]},
  {title: "2", tags: ["weird", "bad"]},
  {title: "3", tags: ["funny", "good"]},
];

而且我希望數組只有“標簽”數組具有“有趣”和“好”的對象。 Array 應該包括“tags”數組包含的所有有趣和好的對象。 不是只包含“有趣”和“好”的對象。

這就是我現在所擁有的，但它不起作用：

let postsfilter = posts.filter(post => post.tags.indexOf(["funny", "good"]));

Answer 1

您可以使用.filter()以及.every()和.includes()來獲得所需的輸出：

 let posts = [ {title: "1", tags: ["funny", "good", "nice"]}, {title: "2", tags: ["weird", "bad"]}, {title: "3", tags: ["funny", "good"]}, ]; let filterBy = ["funny", "good"]; let output = posts.filter( ({ tags }) => filterBy.every(s => tags.includes(s)) ); console.log(output);

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Answer 2

您可以使用Array#every獲取wanted數組的所有項目，並使用Array#includes來檢查數組是否包含字符串。

 let posts = [{ title: "1", tags: ["funny", "good", "nice"] }, { title: "2", tags: ["weird", "bad"] }, { title: "3", tags: ["funny", "good"] }], wanted = ["funny", "good"], result = posts.filter(({ tags }) => wanted.every(s => tags.includes(s))); console.log(result);

Answer 3

let postsfilter = posts.filter(post => post.tags.includes("funny") && post.tags.includes("good") );

Answer 4

 let posts = [ {title: "1", tags: ["funny", "good", "nice"]}, {title: "2", tags: ["weird", "bad"]}, {title: "3", tags: ["funny", "good"]}, ]; let filtered = posts.filter((v) => v.tags.includes("funny") && v.tags.includes("good")) console.log(filtered)