[英]Scala, override method on generic type
我正在嘗試構建DSL ,此 DSL 上的方法之一是無參數的,並使用有界泛型類型。 今天我必須添加一個“功能”,理想情況下將使用相同的方法名稱。 但是,因為唯一的參數是通用參數,所以我不能用通常的方式覆蓋它。
是否有允許對不同泛型類型使用相同方法的技巧?
我的方法看起來像:
def ask[H <: Handler] = {
new CommandBuilder[H]
}
class CommandBuilder[H <: Handler] {
def toExecute[C <: H#C](command: C) = {
//...
}
}
我想補充一點:
def ask[S <: State] = {
new QueryBuilder[S]
}
class QueryBuilder[S <: State] {
def toExecute[Q <: S#Q](query: Q) = {
//...
}
}
我想在類型上模式匹配ClassTag
但我需要強類型安全:
Query
Handler
。 ask[State] 必須返回 QueryBuilderCommand
和Query
是唯一支持的類型。 ask
的通用類型只能是Handler
或State
。也許你可以將你的代碼重構為這樣的東西?
sealed trait FooBar
sealed trait Foo extends FooBar {
def process(i: Int): Int
}
object Foo {
implicit final case object FooImpl extends Foo {
override def process(i: Int): Int = i + 1
}
}
sealed trait Bar extends FooBar {
def process(s: String): String
}
object Bar {
implicit final case object BarImpl extends Bar {
override def process(s: String): String = s.toUpperCase
}
}
object Test {
trait FooBarPartiallyApplied[FB <: FooBar] {
type Out
def out: Out
}
object FooBarPartiallyApplied {
type Aux[FB <: FooBar, _Out] = FooBarPartiallyApplied[FB] { type Out = _Out }
implicit final def FooPartiallyAppliedBuilder[F <: Foo]: Aux[F, FooPartiallyApplied[F]] =
new FooBarPartiallyApplied[F] {
override final type Out = FooPartiallyApplied[F]
override final val out: FooPartiallyApplied[F] =
new FooPartiallyApplied[F](dummy = true)
}
implicit final def BarPartiallyAppliedBuilder[B <: Bar]: Aux[B, BarPartiallyApplied[B]] =
new FooBarPartiallyApplied[B] {
override final type Out = BarPartiallyApplied[B]
override final val out: BarPartiallyApplied[B] =
new BarPartiallyApplied[B](dummy = true)
}
final class FooPartiallyApplied[F <: Foo](private val dummy: Boolean) extends AnyVal {
def toExecute(i: Int)(implicit foo: F): Int = foo.process(i)
}
final class BarPartiallyApplied[B <: Bar](private val dummy: Boolean) extends AnyVal {
def toExecute(s: String)(implicit bar: B): String = bar.process(s)
}
}
def ask[FB <: FooBar](implicit pa: FooBarPartiallyApplied[FB]): pa.Out =
pa.out
}
它按預期工作:
Test.ask[Foo.FooImpl.type].toExecute(10)
// res: Int = 11
Test.ask[Foo.FooImpl.type].toExecute("blah")
// Type error.
Test.ask[Bar.BarImpl.type].toExecute(10)
// Type error.
Test.ask[Bar.BarImpl.type].toExecute("blah")
// res: String = "BLAH"
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