如何將文件輸入拆分為2個不同的數組java

Question

如何將文件輸入文本拆分為 2 個不同的數組？ 我想為姓名創建 n 個數組，並為電話號碼創建一個數組。 我設法進行文件輸入，但我嘗試了所有方法，但似乎無法拆分名稱和數字，然后將其放入 2 個不同的數組中。 我是菜鳥請幫忙

這是 phonebook.txt 文件的樣子

斌阿里,1110001111
亞歷克斯·卡德爾，8943257000
Poh Caimon,3247129843
迭戈·阿梅斯基塔,1001010000
泰麥舒,7776665555
喲瑪多，1110002233
Caup Sul,5252521551
這家伙，7776663333
我和我,0009991221
賈斯汀百里香，1113332222
嘿哦，3939399339
自由人，4533819911
彼得·派博，6480013966
威廉姆洛克，9059671045

下面是我的代碼

   import java.io.*;
   import java.util.Scanner;
   import java.io.FileInputStream;
   import java.io.FileNotFoundException;
   import java.io.IOException;
   import java.io.InputStreamReader;
   import java.io.BufferedReader;
   public class demos {
   public static void main(String[]  args){

    FileInputStream Phonebook;  
    DataInputStream In;
    int i = 0;

     String fileInput;  
      try  
      { 

            Phonebook = new FileInputStream("phonebook.txt"); 

            FileReader fr = new FileReader("phonebook.txt");
            BufferedReader br = new BufferedReader(fr);
            String buffer;
            String fulltext="";
            while ((buffer = br.readLine()) != null) {

                fulltext += buffer;

               // System.out.println(buffer);

                String names = buffer;
                char [] Y ; 
                Y = names.toCharArray();
                System.out.println(Y);

      }}
         catch (FileNotFoundException e)  
            { 
            System.out.println("Error - this file does not exist"); 
         }  
        catch (IOException e)   
        { 
            System.out.println("error=" + e.toString() ); 

         }

Answer 1

如果您使用的是 Java 8，您可以簡化它：

import java.io.File;
import java.io.IOException;
import java.nio.file.Files;
import java.util.ArrayList;

public class Test {
    static ArrayList<String> names = new ArrayList<String>();
    static ArrayList<String> numbers = new ArrayList<String>();

    /**
     * For each line, split it on the comma and send to splitNameAndNum()
     */
    public static void main(String[] args) throws IOException {
        Files.lines(new File("L:\\phonebook.txt").toPath())
        .forEach(l -> splitNameAndNum(l.split(",")));
    }

    /**
     * Accept an array of length 2 and put in the proper ArrayList
     */
    public static void splitNameAndNum(String[] arr) {
        names.add(arr[0]);
        numbers.add(arr[1]);
    }
}

在 Java 7 中：

import java.io.BufferedReader;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStreamReader;

import java.util.ArrayList;

public class Test {
    static ArrayList<String> names = new ArrayList<String>();
    static ArrayList<String> numbers = new ArrayList<String>();

    public static void main(String[] args) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(new FileInputStream("L:\\phonebook.txt")));

        String line;

        while ((line = br.readLine()) != null) {
            splitNameAndNum(line.split(","));
        }
    }

    /**
     * Accept an array of length 2 and put in the proper ArrayList
     */
    public static void splitNameAndNum(String[] arr) {
        names.add(arr[0]);
        numbers.add(arr[1]);
    }
}

Answer 2

對於完整的功能（而不是命令式）解決方案，我建議您使用以下解決方案：

public static void main(String[] args) throws IOException {
    Object[] names = Files.lines(new File("phonebook.txt").toPath()).map(l -> l.split(",")[0]).toArray();
    Object[] numbers = Files.lines(new File("phonebook.txt").toPath()).map(l -> l.split(",")[1]).toArray();


    System.out.println("names in the file are : ");
    Arrays.stream(names).forEach(System.out::println);
    System.out.println("numbers in the file are : ");
    Arrays.stream(numbers).forEach(System.out::println);
}

names in the file are : Bin Arry Alex Cadel Poh Caimon Diego Amezquita Tai Mai Shu Yo Madow Caup Sul This Guy Me And I Justin Thyme Hey Oh Free Man Peter Piper William Mulock numbers in the file are : 1110001111 8943257000 3247129843 1001010000 7776665555 1110002233 5252521551 7776663333 0009991221 1113332222 3939399339 4533819911 6480013966 9059671045輸出names in the file are : Bin Arry Alex Cadel Poh Caimon Diego Amezquita Tai Mai Shu Yo Madow Caup Sul This Guy Me And I Justin Thyme Hey Oh Free Man Peter Piper William Mulock numbers in the file are : 1110001111 8943257000 3247129843 1001010000 7776665555 1110002233 5252521551 7776663333 0009991221 1113332222 3939399339 4533819911 6480013966 9059671045

正如你所看到的，函數式編程既簡短又聰明…… 當你習慣時很容易