從指向同一個表的兩個關系中過濾 first_name 和 last_name

Question

我在user表中有列first_name和last_name ，這又與order_item表相關，其中instructor_id和user_id id都鏈接到user表。

現在我在OrderItem模型中定義了關系，例如：

public function getInstructor() {
        return $this->hasOne(User::className(), ['id' => 'instructor_id']);
    }

和

public function getCustomerName() {
        return $this->hasOne(User::className(), ['id' => 'user_id']);
    }

並在OrderSearch模型中

public $instructor;
public $name;

$query->joinWith(['instructor','location1','customerName n']);        

$query->andFilterWhere(['like', 'concat(user.first_name," ",user.last_name)',  $this->name]) 
        ->$query->andFilterWhere(['like', 'concat(user.first_name," ",user.last_name)',  $this->instructor]);

現在我收到類似的錯誤

Method yii\db\ActiveQuery::__toString() must not throw an exception, 
caught Exception: Serialization of 'Closure' is not allowed

如果我在 joinwith 中刪除別名 n，則會收到如下錯誤：語法錯誤或訪問沖突：1066 不是唯一的表/別名：'user'

The SQL being executed was: SELECT COUNT(*) FROM `order_item` LEFT JOIN `user` ON
`order_item`.`instructor_id` = `user`.`id` LEFT JOIN `location` ON `order_item`.`location_id` =  
`location`.`id` LEFT JOIN `user` ON `order_item`.`user_id` = `user`.`id`

Answer 1

您可以嘗試使其與此類似：

class Order {
...
  //first relation with table COMPANY
  public function getCustomer()
  {
      return $this->hasOne( Company::className(), ['id' => 'customerid'] ) //table COMPANY
                  ->andOnCondition( [ '==relationAlias==.type' => 'customer' ] );
  }

  //second relation with table COMPANY
  public function getSupplier()
  {
      return $this->hasOne( Company::className(), ['id' => 'supplierid'] ) //table COMPANY
                  ->andOnCondition( [ '==relationAlias==.type' => 'supplier' ] );
  }
...
}

然后我們可以寫

$orders = Order::find()
                   ->alias( 'o' )
                   ->innerJoinWith('customer c')
                   ->innerJoinWith('supplier s');

構建查詢

select o.* from order o
join company c on c.id = o.customerid and c.type = 'customer'
join company s on s.id = o.supplierid and s.type = 'supplier'

這個問題是在 github 提出的解決方案提出的： https : //github.com/yiisoft/yii2/issues/10883

Answer 2

這比我想的要簡單得多，但花了很多時間來解決。 但我仍然不清楚為什么問題中的方法不起作用。

就像我所做的那樣，我將查詢分開如下並在查詢中使用了別名。

現存的

$query->andFilterWhere(['like', 'concat(user.first_name," ",user.last_name)',  $this->name]) 
->$query->andFilterWhere(['like', 'concat(user.first_name," ",user.last_name)',  $this->instructor]);

更新

$query->andFilterWhere(['like', 'concat(n.first_name," ",n.last_name)',  $this->name]); 
$query->andFilterWhere(['like', 'concat(user.first_name," ",user.last_name)',  $this->instructor]);

它工作正常。