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[英]How do I update a dynamically created number with an AJAX success function?
[英]How do i return an ajax success function to the method it was called
我想將 ajax 返回值返回到我調用它的函數中,但沒有返回任何數據。
function payment {
var x = payment_status(status)
}
function payment_status (status)
{
return $.ajax({
url: "http://127.0.0.1:81/public/api/payment_status",
type: 'POST',
'content-type':'application/X-WWW-form-urlencoded',
'Accept': 'application/json',
data: {
'status' : status,
}, success: function(response){}
});
}
$.ajax() 返回 thenable 或 Promise(在 jquery 3+ 中)參見https://www.promisejs.org/或MDN 上的 Promise (或者這個答案)
所以你可以使用async 函數(但也可以用 babel 轉譯它):
async function payment() {
try {
var response = await payment_status(status);
} catch (error) {
// Handle error
}
}
function payment_status(status) {
return $.ajax({
url: "http://127.0.0.1:81/public/api/payment_status",
type: "POST",
"content-type": "application/X-WWW-form-urlencoded",
Accept: "application/json",
data: {
status: status
});
}
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