僅當值等於或大於 3,500 時求和？

Question

有如下 3 個交易，我只想對價值等於或大於 3,500 的交易編號求和：

transaction no.   total
0001              1,000 
0001              2,000 
0001              3,000 
0001              4,000 

0002              2,000 
0002              3,000 

0003              1,000 
0003              1,000 
0003              1,000 

這是我期望的結果：

transaction no.   total
0001              10,000 
0002              5,000 

當然，交易沒有。 0003 不會顯示，因為它低於 3,500。

Answer 1

將group by與Having Clause

select transactionNo,sum(total) as totalval
from tablename
group by transactionNo
having sum(total)>3500

Answer 2

你只需要使用如下的have子句：

SELECT transactionNo, SUM(total) AS total
FROM myTable
GROUP BY transactionNo
HAVING SUM(total) > 3500

Answer 3

HAVING 子句被添加到 SQL 中，因為 WHERE 關鍵字不能與聚合函數一起使用。

SELECT column_name(s)
FROM table_name
WHERE condition
GROUP BY column_name(s)
HAVING condition
ORDER BY column_name(s);


SELECT transactionNo, SUM(total) AS total
FROM table_name
GROUP BY transactionNo
HAVING SUM(total) > 3500

Answer 4

您可以使用以下代碼：

SELECT DISTINCT     transactionNo,
   runningtotal
FROM   (
       SELECT myTable1.transactionNo,
              myTable1.total,
              SUM(myTable2.total) AS runningtotal
       FROM   myTable myTable1
              INNER JOIN myTable myTable2
                   ON  myTable1.transactionNo = myTable2.transactionNo
       GROUP BY
              myTable1.transactionNo,
              myTable1.total
   )            result
WHERE  runningtotal > 3500

或者您可以使用窗口函數並使用CTE

;WITH ResultTable AS (
      SELECT DISTINCT transactionNo,
             SUM(total) OVER(PARTITION BY transactionNo) AS total
      FROM   myTable
  )

SELECT *
FROM   ResultTable
WHERE  ResultTable.total > 3500