![](/img/trans.png)
[英]MySQL Group By: How exclude group if at least one row contain value?
[英]How do I filter out a group where there is at least one occurrence of a value?
在下面的示例數據中,我只需要通過caseid_i顯示ContactType不等於 'CLOSR' 的記錄,但在下面的代碼中,它使用 CLOSR 過濾掉任何內容,但不通過 CaseID_I 過濾掉任何內容。 因此,如果 Caseid_i 中的至少一個具有“CLOSR”的 ContactType,我需要過濾掉整個 CaseID。 因此,對於 CaseID_i 51709,caseid_i 根本不會出現在我的結果中,因為至少有一個“ContactTypes”是 CLOSR,而 51715 也是如此。
SELECT C.[cdcpincid_c]
,I.[caseid_i]
,I.echono_c
,C.[close_d] AS ClosureDate
,C.[clinician_c] AS ClosureClinician
,N.[contacttyp_c] AS ContactType
,SC.StaffName AS ClosureStaffName
,I.Refdate_d
FROM [cd].[tb_cdcp_case] C
INNER JOIN [cd].[tb_cdcp_incident] I ON I.[uniqueid_c] = C.[cdcpincid_c]
INNER JOIN [cd].[tb_cdcp_clientcontact] N ON I.[uniqueid_c] = N.[cdcpincid_c]
LEFT OUTER JOIN [dbo].[vCDCP_Staff] SC ON C.clinician_c = SC.Staffcode_c
GROUP BY C.[cdcpincid_c]
,I.[caseid_i]
,I.echono_c
,C.[close_d]
,C.[clinician_c]
,N.[contacttyp_c]
,SC.StaffName
,I.Refdate_d
HAVING sum(CASE
WHEN N.[contacttyp_c] = 'CLOSR'
THEN 1
ELSE 0
END) = 0
AND C.[close_d] IS NOT NULL
AND I.echono_c <> 'OC'
從where
子句中刪除條件並將其切換為having
子句:
having sum(case when ContactType = 'CLOSR' then 1 else 0 end) = 0
編輯:
我知道了。 您正在為每個caseid
返回多行。 在這種情況下,也可以使用窗口函數:
having sum(sum(case when ContactType = 'CLOSR' then 1 else 0 end)) over (partition by caseid) = 0
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.