[英]Mapping XMLs with different schemas to the same classes using JAXB
我有這兩種沒有預定義模式的 XML:
<root-a>
<a-item id="a1">
<name>Name of A1</name>
<a-item id="a11">
<name>Name of A11</name>
</a-item>
<a-item id="a12">
<name>Name of A12</name>
<a-item id="a121">
<name>Name of A121</name>
</a-item>
<a-item id="a122">
<name>Name of A122</name>
</a-item>
</a-item>
</a-item>
<a-item id="a2">
<name>Name of A2</name>
</a-item>
</root-a>
<root-b>
<b-item id="b1">
<name>Name of B1</name>
<b-item id="b11">
<name>Name of B11</name>
</b-item>
<!-- etc., similar to A -->
</b-item>
</root-b>
這些項目可以嵌套到任意深度。 結構相同,但根元素和項目元素的名稱不同。 如何將其映射到單個 Java 類結構,例如。 像這樣(省略 getter 和 setter)使用 JAXB:
public class Root {
private List<Item> items;
}
public class Item {
private String id;
private String name;
private List<Item> items;
}
我可以使用 JAXB 注釋僅映射一個 XML 結構,但我不知道如何同時適應這兩個 XML。 我可以使用通用接口為 A 和 B 創建並行層次結構,但我希望有一個更簡潔的解決方案。
這是基於您的描述的 XML 架構:
<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified" attributeFormDefault="unqualified">
<!-- Root elements -->
<xs:element name="root-a" type="rootAType"/>
<xs:element name="root-b" type="rootBType"/>
<!-- root-a type -->
<xs:complexType name="rootAType">
<xs:sequence>
<xs:element name="a-item" type="itemAType" minOccurs="0" maxOccurs="unbounded"/>
</xs:sequence>
</xs:complexType>
<!-- root-b type -->
<xs:complexType name="rootBType">
<xs:sequence>
<xs:element name="b-item" type="itemBType" minOccurs="0" maxOccurs="unbounded"/>
</xs:sequence>
</xs:complexType>
<!-- abstract item type -->
<xs:complexType name="itemType" abstract="true">
<xs:sequence>
<xs:element name="name" type="xs:string"/>
</xs:sequence>
<xs:attribute name="id" type="xs:string"/>
</xs:complexType>
<!-- item-a type -->
<xs:complexType name="itemAType">
<xs:complexContent>
<xs:extension base="itemType">
<xs:sequence>
<xs:element name="a-item" type="itemAType" minOccurs="0" maxOccurs="unbounded"/>
</xs:sequence>
</xs:extension>
</xs:complexContent>
</xs:complexType>
<!-- item-b type -->
<xs:complexType name="itemBType">
<xs:complexContent>
<xs:extension base="itemType">
<xs:sequence>
<xs:element name="b-item" type="itemBType" minOccurs="0" maxOccurs="unbounded"/>
</xs:sequence>
</xs:extension>
</xs:complexContent>
</xs:complexType>
</xs:schema>
基於此模式創建了以下類:
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "itemType", propOrder = {
"name"
})
@XmlSeeAlso({
ItemAType.class,
ItemBType.class
})
public abstract class ItemType {
@XmlElement(required = true)
protected String name;
@XmlAttribute(name = "id")
protected String id;
public String getName() {
return name;
}
public void setName(String value) {
this.name = value;
}
public String getId() {
return id;
}
public void setId(String value) {
this.id = value;
}
}
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "itemAType", propOrder = {
"aItem"
})
public class ItemAType
extends ItemType
{
@XmlElement(name = "a-item")
protected List<ItemAType> aItem;
public List<ItemAType> getAItem() {
if (aItem == null) {
aItem = new ArrayList<ItemAType>();
}
return this.aItem;
}
}
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "itemBType", propOrder = {
"bItem"
})
public class ItemBType
extends ItemType
{
@XmlElement(name = "b-item")
protected List<ItemBType> bItem;
public List<ItemBType> getBItem() {
if (bItem == null) {
bItem = new ArrayList<ItemBType>();
}
return this.bItem;
}
}
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "rootAType", propOrder = {
"aItem"
})
public class RootAType {
@XmlElement(name = "a-item")
protected List<ItemAType> aItem;
public List<ItemAType> getAItem() {
if (aItem == null) {
aItem = new ArrayList<ItemAType>();
}
return this.aItem;
}
}
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "rootBType", propOrder = {
"bItem"
})
public class RootBType {
@XmlElement(name = "b-item")
protected List<ItemBType> bItem;
public List<ItemBType> getBItem() {
if (bItem == null) {
bItem = new ArrayList<ItemBType>();
}
return this.bItem;
}
}
這似乎有點太復雜了,但是如果您在 a-item 和 b-item 之間有更多共同的功能,則結構會變得更加方便。
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