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[英]Serializing one to many relationships nested json with flask marshmallow
[英]How to join nested schema into one JSON object with Flask Marshmallow
我在將兩個模式連接到一個嵌套的 JSON 對象中時遇到問題。 此 API 返回 JSON 作為 3 個相關表連接查詢的結果。 在我進行查詢之后,我使用了從這里引用的兩個 Marshmellow 模式。 但是響應並不像預期的那樣,這里是響應:
{
"message": "success",
"device": [
{
"device_name": "Kamar Tidur Utama"
}
],
"sensor": [
{
"value": 23.3683,
"sensor_name": "Temperature"
},
{
"value": 0.0,
"sensor_name": "Motion"
},
{
"value": 90.12,
"sensor_name": "Humidity"
},
{
"value": 15.8667,
"sensor_name": "Current 1"
},
{
"value": 15.0333,
"sensor_name": "Current 2"
}
]
}
我想要的是“傳感器”對象放在“設備”中。 很多設備都有很多這樣的傳感器:
{
"message": "success",
"device": [
{
"device_name": "Kamar Tidur Utama"
"sensor": [
{
"value": 23.3683,
"sensor_name": "Temperature"
},
{
"value": 0.0,
"sensor_name": "Motion"
},
{
"value": 90.12,
"sensor_name": "Humidity"
},
{
"value": 15.8667,
"sensor_name": "Current 1"
},
{
"value": 15.0333,
"sensor_name": "Current 2"
}
]
}
]
}
這是我的三個相關模型:
Device.py(一種查詢API的方法)
@classmethod
def get_device_sensor(cls):
device_sensor_schema = DeviceSensorSchema(many=True)
sensor_value_schema = SensorValueSchema(many=True)
device = Device.query.join(SensorData, Device.id == SensorData.device_id)\
.add_columns(Device.name.label('device_name'))
print(device)
sensor = Sensor.query.join(SensorData, Sensor.id == SensorData.sensor_id)\
.add_columns(Sensor.name.label('sensor_name'), SensorData.value.label('value'))
res_device = device_sensor_schema.dump(device, many=True)
res_sensor = sensor_value_schema.dump(sensor, many=True)
if device:
return jsonify({'message': 'success', 'device': res_device, 'sensor': res_sensor})
else:
return {'message': 'Table device is empty'}, 404
Device.py(兩個棉花糖架構)
class SensorValueSchema(ma.Schema):
sensor_name = fields.String()
value = fields.Float()
ordered=True
class DeviceSensorSchema(Schema):
device_name = fields.String()
sensors = fields.List(fields.Nested(SensorValueSchema))
Device.py(模型類)
class Device(db.Model):
__tablename__ = "devices"
id = db.Column(db.Integer, primary_key=True)
user_id = db.Column(db.Integer, db.ForeignKey('users.id'))
name = db.Column(db.String(255))
serial_number = db.Column(db.String(255), unique=True)
used_relay = db.Column(db.Integer, default=0)
created_at = db.Column(db.DateTime(timezone=True), server_default=db.func.now())
updated_at = db.Column(db.DateTime(timezone=True), onupdate=db.func.now())
switches = db.relationship('Switch', backref='device', lazy='dynamic')
power_usages = db.relationship('PowerUsage', backref='device', lazy='dynamic')
power_expenses = db.relationship('PowerExpense', backref='device', lazy='dynamic')
behaviors_dataset = db.relationship('BehaviorDataset', backref='device', lazy='dynamic')
usage_histories = db.relationship('UsageHistory', backref='device', lazy='dynamic')
sensors_data = db.relationship('SensorData', backref='device', lazy='dynamic')
notifications = db.relationship('Notification', backref='device', lazy='dynamic')
device_serial_number = db.relationship('DeviceSerialNumber', backref='device', lazy='dynamic')
Sensor.py(模型類)
class Sensor(db.Model):
__tablename__ = "sensors"
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String(120))
created_at = db.Column(db.DateTime(timezone=True), server_default=db.func.now())
updated_at = db.Column(db.DateTime(timezone=True), onupdate=db.func.now())
sensors_data = db.relationship('SensorData', backref='sensor', lazy='dynamic')
SensorData.py(模型類)
class SensorData(db.Model):
__tablename__ = "sensors_data"
id = db.Column(db.Integer, primary_key=True)
device_id = db.Column(db.Integer, db.ForeignKey('devices.id'))
sensor_id = db.Column(db.Integer, db.ForeignKey('sensors.id'))
value = db.Column(db.Float)
created_at = db.Column(db.DateTime(timezone=True), server_default=db.func.now())
updated_at = db.Column(db.DateTime(timezone=True), onupdate=db.func.now())
您應該將sensor
對象分配給device
列表中的每個條目。 我達到理想結果的愚蠢方式:
@classmethod
def get_device_sensor(cls):
device_sensor_schema = DeviceSensorSchema(many=True)
sensor_value_schema = SensorValueSchema(many=True)
device = Device.query.join(SensorData, Device.id == SensorData.device_id)\
.add_columns(Device.name.label('device_name'))
print(device)
sensor = Sensor.query.join(SensorData, Sensor.id == SensorData.sensor_id)\
.add_columns(Sensor.name.label('sensor_name'), SensorData.value.label('value'))
res_device[0].sensors = sensor
res_device = device_sensor_schema.dump(device, many=True)
if device:
return jsonify({'message': 'success', 'device': res_device})
else:
return {'message': 'Table device is empty'}, 404
解決這個問題的更好方法是使用映射的 SQLAlchemy 對象。 在這種情況下Device.sensors_data
。
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