[英]SSMS: How to return only the value in the last row for each month/year instead of every row?
我正在使用的代碼返回月/年中的所有日期,但我只希望它返回最后一個日期行而不是所有每日行。
這是我正在使用的代碼。
;WITH OIL_INDEX AS (
SELECT PRODUCT_SYMBOL
,CONTRACT_MONTH
,CONTRACT_YEAR
,CONTRACT_DETAIL
,TRADEDATE
,SETTLE
,AVG(SETTLE) OVER (
PARTITION BY CONTRACT_DETAIL, YEAR(TRADEDATE), MONTH(TRADEDATE)
ORDER BY TRADEDATE
ROWS BETWEEN 29 PRECEDING and CURRENT ROW
) AS MA30
,YEAR(TRADEDATE) AS TRADEYEAR
,MONTH(TRADEDATE) AS TRADEMONTH
,DAY(TRADEDATE) AS TRADEDAY
,row_number() OVER(
PARTITION BY CONTRACT_DETAIL, TRADEDATE
ORDER BY TRADEDATE DESC) AS RowNum
FROM Pricing.dbo.MasterReport$
)
SELECT PRODUCT_SYMBOL
,CONTRACT_MONTH
,CONTRACT_YEAR
,CONTRACT_DETAIL
,TRADEDATE
,TRADEYEAR
,TRADEMONTH
,TRADEDAY
,SETTLE
,MA30
FROM OIL_INDEX
WHERE RowNum = 1 AND PRODUCT_SYMBOL
IN ('CL','CY','WJ')
ORDER BY PRODUCT_SYMBOL ASC, CONTRACT_DETAIL ASC,TRADEYEAR ASC, TRADEMONTH ASC, TRADEDAY ASC
這是給出的結果。
這是我想要的。
我認為你只需要修改窗口函數的PARTITION BY
子句:
前:
ROW_NUMBER() OVER(
PARTITION BY CONTRACT_DETAIL, TRADEDATE
ORDER BY TRADEDATE DESC
) AS RowNum
后:
ROW_NUMBER() OVER(
PARTITION BY CONTRACT_DETAIL, YEAR(TRADEDATE), MONTH(TRADEDATE)
ORDER BY TRADEDATE DESC
) AS RowNum
基本原理:您的分區子句為每個不同的(CONTRACT_DETAIL, TRADEDATE )
元組創建一個新組; 這是生成很多組的利利,每個組可能只有一個記錄。 相反,您希望按合同和月份進行分區,然后按交易日期對每個組中的記錄進行排名。
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