[英]How to stop my code from printing "Ascending" more than once?
我的代碼是:
Scanner sc=new Scanner(System.in);
System.out.println("Type in your order(ex.5 7 4 6 8 3 9 2 0 1 - SPACES REQUIRED): ");
String input=sc.nextLine();
for(int i=0;i<input.length(); i++) {
String[] b=input.split(" ");
if(Integer.valueOf(b[i]) < Integer.valueOf(b[i+1])) {
System.out.println("Acsending");
}
else { // When condition is false
System.out.println("Mixed");
}
}
但是當我的輸入是1 2 3 4 5 6
,輸出是: Ascending Ascending Ascending Ascending Ascending
而當我的輸入是1 4 2 5 2
,輸出是, Ascending Mixed Ascending Mixed
如何使代碼打印僅當輸入是混合還是升序?
在我之前回答的人(Elliott Frisch)是專業人士,我不知道這條線是做什么的,還有那些 :: 是什么
Arrays.stream(input.split("\\s+")).mapToInt(Integer::parseInt).toArray();
我自己是初學者,這就是我做到的
public static void main(String[] args)
{
Scanner sc =new Scanner(System.in);
System.out.println("Type in your order(ex.5 7 4 6 8 3 9 2 0 1 - SPACES REQUIRED): ");
String input=sc.nextLine();
String[] b=input.split(" ");
sc.close(); //Always Close Scanner after user :)
boolean isMixed = false; // Flag
for(int i=0; i < input.length()/2; i++) //input.length() is equal to number + Spaces we don't want spaces
{
//Integer.parseInt(b[i]) converting string to Integer
if(Integer.parseInt(b[i]) < Integer.parseInt(b[i+1]))
{
isMixed = false;
}
else
{
isMixed = true;
}
}
if(isMixed)
{
System.out.println("Mixed");
} else
{
System.out.println("Ascending");
}
}
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