為Javascript中的不同鍵從JSON獲取多個集合

Question

嗨，我被這個問題困住了。 希望有人能給我一些建議。

我有一個 JSON，其中包含我正在處理的應用程序的最后一天更改。 我想從中獲取 3 個數據集。 並希望保持正確的日期順序，如下例所示：

"log": [{
        "objectname": "Lorem Ipsum",
        "type": "CREATE",
        "timenormal": "Sun Feb 09 2020 22:02:26 GMT+0100",
        "closesthours": 22
    }, {
        "objectname": "This is a Dummy",
        "type": "CREATE",
        "timenormal": "Sun Feb 09 2020 23:27:46 GMT+0100",
        "closesthours": 23
    },{
        "objectname": "Deleted test",
        "type": "DELETE",
        "timenormal": "Mon Feb 10 2020 00:30:14 GMT+0100",
        "closesthours": 1
    },{
        "objectname": "Qwerty",
        "type": "CREATE",
        "timenormal": "Mon Feb 10 2020 00:45:04 GMT+0100",
        "closesthours": 1
    },{
        "objectname": "Deleted test",
        "type": "DELETE",
        "timenormal": "Mon Feb 10 2020 04:45:14 GMT+0100",
        "closesthours": 5
    }, {
        "objectname": "Hello World",
        "type": "CREATE",
        "timenormal": "Mon Feb 10 2020 10:51:22 GMT+0100",
        "closesthours": 11
    }, {
        "objectname": "Another one",
        "type": "CREATE",
        "timenormal": "Mon Feb 10 2020 10:41:22 GMT+0100",
        "closesthours": 11
    }, {
        "objectname": "ABC",
        "type": "CREATE",
        "timenormal": "Mon Feb 10 2020 21:16:57 GMT+0100",
        "closesthours": 21
    }, {
        "objectname": "test dummy",
        "type": "DELETE",
        "timenormal": "Mon Feb 10 2020 21:17:00 GMT+0100",
        "closesthours": 21
    }
]

我知道以下可以使用地圖作為“最近的時間”：

jsondata['log'].map(function(value, index) {return value['closesthours']});
[22, 23, 1, 1, 5, 11, 11, 21, 21]

從那以后，我被困住了。 我想要的3 個數據集是：

1.)結合最近時間的地圖：

{"hours":"22,23,1,5,11,21"}

2 & 3)然后我真的想通過最接近的小時數在數據集中為兩種類型 (DELETE 和 CREATE) 計算出現次數例如，我想獲得以下結果（如果該類型沒有 te，則為 0最近時間）：

{"type":"CREATE","groupcount":"1,1,1,0,2,1"}
{"type":"DELETE","groupcount":"0,0,1,1,0,1"}

我怎樣才能在 javascript 中做到這一點？

Answer 1

您可以首先使用唯一的小時數組和每種類型構建一個對象，然后使用另一個循環使用先前創建的對象為每種類型填充groupcount數組。

 const data = [{"objectname":"Lorem Ipsum","type":"CREATE","timenormal":"Sun Feb 09 2020 22:02:26 GMT+0100","closesthours":22},{"objectname":"This is a Dummy","type":"CREATE","timenormal":"Sun Feb 09 2020 23:27:46 GMT+0100","closesthours":23},{"objectname":"Deleted test","type":"DELETE","timenormal":"Mon Feb 10 2020 00:30:14 GMT+0100","closesthours":1},{"objectname":"Qwerty","type":"CREATE","timenormal":"Mon Feb 10 2020 00:45:04 GMT+0100","closesthours":1},{"objectname":"Deleted test","type":"DELETE","timenormal":"Mon Feb 10 2020 04:45:14 GMT+0100","closesthours":5},{"objectname":"Hello World","type":"CREATE","timenormal":"Mon Feb 10 2020 10:51:22 GMT+0100","closesthours":11},{"objectname":"Another one","type":"CREATE","timenormal":"Mon Feb 10 2020 10:41:22 GMT+0100","closesthours":11},{"objectname":"ABC","type":"CREATE","timenormal":"Mon Feb 10 2020 21:16:57 GMT+0100","closesthours":21},{"objectname":"test dummy","type":"DELETE","timenormal":"Mon Feb 10 2020 21:17:00 GMT+0100","closesthours":21}] const {hours, types} = data.reduce((r, {type, closesthours}, i) => { r.hours = [...new Set([...r.hours, closesthours] || [])] r.types[type] = {type, groupcount: []} return r; }, {hours: [], types: {}}); data.forEach(({type, closesthours}) => { const index = hours.indexOf(closesthours); for(let t in types) { if(types[t].groupcount[index] == undefined) { types[t].groupcount[index] = 0 } if(t == type) { types[t].groupcount[index] += 1 } } }); console.log(hours) console.log(Object.values(types))