MySQL GROUP BY if 條件

Question

僅當具有相同movie_id所有行都具有convert=2我才想返回movie_id 。 如果具有相同movie_id的行的convert=0則不返回movie_id 。

例子：

這應該不返回任何內容，因為所有三行都具有相同的 movie_id 但在最后一行上 convert=0

+----+----------+------------+------------+--------------+---------+
| id | movie_id |    lang    | email_sent | user_request | convert |
+----+----------+------------+------------+--------------+---------+
| 1  |    1     |   german   |     0      |      1       |    2    |
| 2  |    1     |   french   |     0      |      1       |    2    |
| 3  |    1     |   english  |     0      |      1       |    0    |
+----+----------+------------+------------+--------------+---------+

這應該返回movie_id因為所有三行都具有相同的movie_id，並且所有行的convert=2

+----+----------+------------+------------+--------------+---------+
| id | movie_id |    lang    | email_sent | user_request | convert |
+----+----------+------------+------------+--------------+---------+
| 1  |    1     |   german   |     0      |      1       |    2    |
| 2  |    1     |   french   |     0      |      1       |    2    |
| 3  |    1     |   english  |     0      |      1       |    2    |
+----+----------+------------+------------+--------------+---------+

這是我的查詢，但當我嘗試使用第二個示例數據時movie_id ，仍然返回movie_id

SELECT movie_id
from movie_subtitles
WHERE email_sent=0 AND user_request=1
GROUP BY CASE WHEN `convert`=2 THEN movie_id END
ORDER BY id ASC
LIMIT 1

我該如何解決？

Answer 1

你需要一個像這樣的 HAVING 子句：

SELECT movie_id
FROM movie_subtitles
WHERE email_sent=0 AND user_request=1
GROUP BY movie_id
HAVING SUM(Convert <> 2) = 0