[英]Finding palindrome number in java
import java.util.*;
class Example{
public static void main(String args[]){
Scanner input=new Scanner(System.in);
System.out.print("Input a prefer number :");
int num=input.nextInt();
int reverse=0;
while(num!=0){
int num1=num%10;
reverse=(reverse*10)+num1;
num/=10;
}
System.out.println("Reverse num is "+reverse);
if(num==reverse){
System.out.println("The number is palindrome");
}else{
System.out.println("Try again");
}
}
}
我想通過鍵盤輸入數字時確認它是否是回文數。但我無法得到它。在我的代碼的第7行中,我將變量“reverse”初始化為0。所以當我在第 14 行設置一個條件,“反向”作為 0。那應該是,但我想讓“反向”等於第 10 行中的值。我該怎么辦?
在更改時將 num 分配給另一個變量
import java.util.*;
class Example{
public static void main(String args[]){
Scanner input=new Scanner(System.in);
System.out.print("Input a prefer number :");
int num=input.nextInt();
int number = num ; // assign to anaother variable as num gets changed
int reverse=0;
while(num!=0){
int num1=num%10;
reverse=(reverse*10)+num1;
num/=10;
}
System.out.println("Reverse num is "+reverse);
if(number==reverse){
System.out.println("The number is palindrome");
}else{
System.out.println("Try again");
}
}
}
您可以考慮將數字視為字符串。
Scanner input=new Scanner(System.in);
System.out.print("Input a preferred number :");
String str = input.nextLine();
StringBuilder sb = new StringBuilder(str);
String reverse = sb.reverse().toString();
System.out.println("Reverse num is "+reverse);
if(str.equals(reverse)){
System.out.println("The number is palindrome");
}else{
System.out.println("Try again");
}
}
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