[英]Javascript array search filter
我有場景,提供示例 JSON 數據:
[{
"name": "Joe",
"age": "28",
"hobby": ["Reading", "Chilling", "Cycling"]
},
{
"name": "Beck",
"age": "25",
"hobby": ["Drinking", "Cycling"]
},
{
"name": "Candace",
"age": "24",
"hobby": ["Reading", "Singing"]
}]
假設上面的數組顯示在網頁的某個列表中。
我有 2(兩個)搜索下拉列表,其中包含多項選擇來搜索姓名和年齡。
為了搜索愛好,我的代碼是(在 ReactJS 中):
filteredPersons = this.state.personList.filter( person =>{
return person.hobby.some(v=> filterHobby.indexOf(v) !== -1)
});
即:
personList
是來自上面 JSON 的數組列表;filterHobby
是來自多個選擇的數組列表,例如:如果filterHobby = ["Reading","Singing"]
,它將顯示 Joe 和 Candace。問題是,如何通過多項選擇搜索年齡?
預期結果:
23-26
將顯示 Beck 和 Candace>27
only將顯示 Joe謝謝你的任何回答。
您可以使用一個帶有所有過濾器的對象,另一個用於保持獲取對象年齡的功能。
var data = [{ name: "Joe", age: "28", hobby: ["Reading", "Chilling", "Cycling"] }, { name: "Beck", age: "25", hobby: ["Drinking", "Cycling"] }, { name: "Candace", age: "24", hobby: ["Reading", "Singing"] }], functions = { '23-26': ({ age }) => age >= 23 && age <= 26, '>27': ({ age }) => age > 27 }, filters = { hobby: ["Reading", "Cycling"], age: ['23-26'] }, result = data.filter(o => filters.hobby.some(v => o.hobby.includes(v)) && filters.age.some(fn => functions[fn](o)) ); console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
您需要使用filter
函數來過濾數組。
我們有一個包含人的數組:
const persons = [
{
"name": "Joe",
"age": "28",
"hobby": ["Reading", "Chilling", "Cycling"]
},
{
"name": "Beck",
"age": "25",
"hobby": ["Drinking", "Cycling"]
},
{
"name": "Candace",
"age": "24",
"hobby": ["Reading", "Singing"]
}
]
然后我們將過濾該數組:
persons.filter((person) => {
return person.age > 27;
})
此代碼返回給我們Joe的信息:
[
{
"name": "Joe",
"age": "28",
"hobby": ["Reading", "Chilling", "Cycling"]
}
]
ageFilters = ['23-26','>27']
selectedFilter = '23-26';
filteredPersons = this.state.persons.filter(({age}) => {
const _age = parseInt(age);
if(selectedFilter === '23-26') { // "23-26"
return (_age>=23) && (_age<=26);
} else if(selectedFilter === '>27') { // "27"
return (_age>27);
} else {
return true;
}
})
為方便起見,您可以創建附加功能ageComparer
const ageComparer = (ageRange, age) => (ageRange === '23-26' ? (age >= 23 && age <= 26) : age >=27)
然后在過濾過程中使用它
// ageFilter will be taken from drom down
const ageFilter = ['23-26'];
person.filter(p => p.hobby.some(v=> filterHobby.indexOf(v) !== -1) && ageFilter.some(a => ageComparer(a, +p.age)))
對於按年齡搜索人員,您可以像這樣制作一個選定年齡的數組。
let ages = ['23','24','25'];
像這樣的代碼
persons.filter(item=> {return ages.indexOf(item.age)!== -1 })
這個返回 person 數組,這些數組在 Ages 數組中匹配
輸出:
[
{ name: 'Beck', age: '25', hobby: [ 'Drinking', 'Cycling' ] },
{ name: 'Candace', age: '24', hobby: [ 'Reading', 'Singing' ] }
]
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