[英]Returning a 2D Array from a method using the class name as the input
我在return gameBoard;
行上收到錯誤消息“類型不匹配無法從 String[][] 轉換為 GameBoard[][]” return gameBoard;
. 如何更改我的公共類 GameBoard 以便我能夠在 2D 數組中返回字符串值? (我不想將方法返回類型更改為 String[][])
public class GameBoard {
String[][] gameBoard;
/**
* Constructor
*/
public GameBoard() {
gameBoard = new String[4][5];
}
/**
* Filling the playable board with Strings
* @return
*/
public GameBoard[][] fillGameBoard() {
gameBoard[0][0] = new String("1");
gameBoard[0][1] = new String("2");
gameBoard[0][2] = new String("3");
gameBoard[0][3] = new String("4");
gameBoard[0][4] = new String("5");
gameBoard[1][0] = new String("6");
gameBoard[1][1] = new String("7");
gameBoard[1][2] = new String("8");
gameBoard[1][3] = new String("9");
gameBoard[1][4] = new String("10");
gameBoard[2][1] = new String("11");
gameBoard[2][2] = new String("12");
gameBoard[2][3] = new String("13");
gameBoard[3][1] = new String("14");
gameBoard[3][2] = new String("15");
gameBoard[3][3] = new String("16");
return gameBoard;
}```
發生這種情況是因為您告訴編譯器您將返回GameBoard[][]
類型,但實際上返回的是String[][]
類型,您可能會因為以與命名類相同的方式命名成員變量而混淆了自己。 您可能想為它取一個不那么令人困惑的名稱。
通常,您為 GameBoard 定義類的方法很好,因為您可能希望稍后對其執行不同的操作,例如move()
內容從 1 個單元格移動到另一個單元格或其他內容。 但請記住,您的“客戶端類”不知道您的類內部的外觀,因此您不能將GameObject
存儲為String[][]
,反之亦然
這是您的類的示例,其中包含有關如何聲明使用 GameBoard 的變量以及建議的一些評論:(這將無法正常工作,您必須刪除不想使用的方法,因為它們在返回類型)
public class GameBoard {
String[][] gameBoard;
/**
* Constructor
*/
public GameBoard() {
gameBoard = new String[4][5];
}
// Approach 1
public void fillGameBoard() {
gameBoard[0][0] = "1";
gameBoard[0][1] = "2";
gameBoard[0][2] = "3";
gameBoard[0][3] = "4";
gameBoard[0][4] = "5";
gameBoard[1][0] = "6";
gameBoard[1][1] = "7";
gameBoard[1][2] = "8";
gameBoard[1][3] = "9";
gameBoard[1][4] = "10";
gameBoard[2][1] = "11";
gameBoard[2][2] = "12";
gameBoard[2][3] = "13";
gameBoard[3][1] = "14";
gameBoard[3][2] = "15";
gameBoard[3][3] = "16";
}
// Approach 2
// If you really want to go with the way you had your declaration set up
// GameBoard board = new GameBoard().fillGameBoard();
// you would have to do this
public GameBoard fillGameBoard() {
fillGameBoard();
return this;
}
// Approach 3
// If you want to do this, you don't need your class at all and your fillGameBoard
// has to return a String[][] type. I would recommend against it though,
// since you are using a highly object oriented language as Java
public String[][] fillGameBoard() {
fillGameBoard();
return gameBoard;
}
public static void main(String[] args) {
// Approach 1
// I recommend this approach!
GameBoard board2 = new GameBoard();
board2.fillGameBoard();
// Approach 2
GameBoard board = new GameBoard().fillGameBoard();
// Approach 3
String[][] board3 = new GameBoard().fillGameBoard();
}
}
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.