[英]Return resolved promise value
const displayCharacters = async () => {
if(filteredCharacters !== 'default'){
const a = filteredCharacters.map(e => e.name);
const options = {
method: "POST",
headers: { "Content-Type": "application/json" },
body: JSON.stringify({ 'data' : a })
};
const b = await fetch("/image",options).then(res => res.json())
return b;
}else{
return "yikes";
}
}
console.log(displayCharacters());
我有這個獲取請求,但是當我記錄結果時,我看到的是:
Promise {<resolved>: "yikes"}
__proto__: Promise
[[PromiseStatus]]: "resolved"
[[PromiseValue]]: "yikes"
我只想要 promiseValue 而不是整個事情。 我該怎么做呢?
async
函數立即返回一個承諾,而無需等待承諾解決。 您可以改為在函數內部使用 console.log:
const displayCharacters = async () => {
if(filteredCharacters !== 'default'){
const a = filteredCharacters.map(e => e.name);
const options = {
method: "POST",
headers: { "Content-Type": "application/json" },
body: JSON.stringify({ 'data' : a })
};
try {
const b = await fetch("/image",options).then(res => res.json());
console.log(b);
//the better practice is however, to do like:
const b = await fetch("/image",options)
const result = await b.json();
console.log(result );
}
catch(err) {
console.log(err);
}
}else{
console.log("yikes");
}
}
displayCharacters();
我知道使用 fetch 的最好方法是這樣的:
const displayCharacters = async () => {
if(filteredCharacters !== 'default'){
const a = filteredCharacters.map(e => e.name);
const options = {
method: "POST",
headers: { "Content-Type": "application/json" },
body: JSON.stringify({ 'data' : a })
};
const b = await fetch("/image",options)
.then(res => {
// Handle API Errors
if (!res.ok) {
throw Error(res.statusText);
}
// Return if no errors
return res.json();
})
// this is the data you want
.then(data => data)
// it will only reject on network failure or if anything prevented the request from completing
.catch(error => {
console.log(error.message)
});
return b;
}else{
return "yikes";
}
}
基本上,您將兩個 then 和一個 catch 鏈接起來以完全理解響應 - 第一個然后檢查 api 級別的錯誤 - 第二個然后獲取數據 - 當它無法像連接問題一樣到達 api 本身時調用 catch
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