[英]async await in switch case statement don't work
我們可以使用關鍵字 await 在 switch case 語句中等待承諾的解決嗎? 在我的角度組件中,我有以下代碼使我的應用程序崩潰。
switch (this.status) {
case 'opened':
break;
case 'payed':
this.getIntervalStatusSubscription.unsubscribe();
this.localStorageService.storePaymentIsMade(true);
await this.dbService.addOrderPaymentResult(ProcessResult.done, this.printerVMService.getSessionId()).toPromise();
this.router.navigate(['welcome/paying/paying_accepted']);
break;
case 'closed':
this.getIntervalStatusSubscription.unsubscribe();
this.paymentSessionIsClosed = true;
await this.dbService.addOrderPaymentResult(ProcessResult.error, this.printerVMService.getSessionId()).toPromise();
this.router.navigate(['welcome']);
break;
case 'used':
this.getIntervalStatusSubscription.unsubscribe();
this.router.navigate(['welcome']);
break;
default:
console.error('status don\'t exist');
this.utils.displayAlertError(this.device.getIntervalStatus);
this.router.navigate(['welcome']);
}
經過幾次測試,在我看來,錯誤似乎來自以await
開頭的行。 你能告訴我有什么問題嗎? 我想要this.dbService.addOrderPaymentResult(ProcessResult.done, this.printerVMService.getSessionId())
返回一個 observable 在進入this.router.navigate(['welcome/paying/paying_accepted']);
之前同步執行this.router.navigate(['welcome/paying/paying_accepted']);
這就是為什么我選擇使用toPromise()
並await
是的你可以:
async function trySwitch(status) { switch(status) { case 'opened': console.log('1'); break; case 'closed': console.log('2'); await new Promise(r => setTimeout(r, 1000)); console.log('3'); break; } } trySwitch('opened'); trySwitch('closed');
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