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Spring Boot:類型不能為空; 嵌套異常是 java.lang.IllegalArgumentException:運行存儲過程時類型不能為空

[英]Spring Boot: Type cannot be null; nested exception is java.lang.IllegalArgumentException: Type cannot be null when running Stored Procedue

早上好,我是Spring Boot的新手,我正在執行一個休息服務,必須調用存儲在數據庫中的一個過程,問題是你收到手機並且必須返回一個代碼和結果,如下所示:

在此處輸入圖片說明

這是我的代碼:

主類

package com.app.validacion;

import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;

@SpringBootApplication
public class App {

    public static void main(String[] args) {
        SpringApplication.run(App.class, args);
    }
}

控制器

package com.app.validacion.controller;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.web.bind.annotation.GetMapping;
import org.springframework.web.bind.annotation.PathVariable;
import org.springframework.web.bind.annotation.RestController;


import com.app.validacion.dao.DriverBonificadosRepository;
import com.app.validacion.entity.RespuestaVo;

@RestController
public class DriverBonificadosController {

    @Autowired
    private DriverBonificadosRepository dao;

    @GetMapping("/service/{movil}")
    public RespuestaVo  ConsultarMovil(@PathVariable String movil) {
        return dao.validarClienteBonifiado(movil);

    }
}

存儲庫

package com.app.validacion.dao;

import org.springframework.data.jpa.repository.query.Procedure;
import org.springframework.data.repository.CrudRepository;

import com.app.validacion.entity.DriverBonificados;
import com.app.validacion.entity.RespuestaVo;

public interface DriverBonificadosRepository extends CrudRepository<DriverBonificados, Integer> {

    @Procedure(procedureName="ValidacionClienteBonificado")
    RespuestaVo validarClienteBonifiado(String pMovil);
}

我的實體

import javax.persistence.NamedStoredProcedureQueries;
import javax.persistence.NamedStoredProcedureQuery;
import javax.persistence.ParameterMode;
import javax.persistence.StoredProcedureParameter;
import javax.persistence.Table;


@NamedStoredProcedureQueries({
    @NamedStoredProcedureQuery(
            name="SPValidationClienteBonus4G",
            procedureName="ValidacionClienteBonificado",
            parameters = {
                    @StoredProcedureParameter(mode=ParameterMode.IN, name="p_movil",type=String.class), 
                    @StoredProcedureParameter(mode=ParameterMode.OUT, name="code",type=String.class),
                    @StoredProcedureParameter(mode=ParameterMode.OUT, name="result",type=String.class),
            })

})

@Entity
@Table
public class DriverBonificados {

    @Id
    private int id;
    public int getId() {
        return id;
    }
    public void setId(int id) {
        this.id = id;
    }
    public String getMovil() {
        return movil;
    }
    public void setMovil(String movil) {
        this.movil = movil;
    }
    public String getContador() {
        return contador;
    }
    public void setContador(String contador) {
        this.contador = contador;
    }
    public Date getFecha_driver() {
        return fecha_driver;
    }
    public void setFecha_driver(Date fecha_driver) {
        this.fecha_driver = fecha_driver;
    }
    public Date getFecha_alta() {
        return fecha_alta;
    }
    public void setFecha_alta(Date fecha_alta) {
        this.fecha_alta = fecha_alta;
    }
    public Date getFecha_fin() {
        return fecha_fin;
    }
    public void setFecha_fin(Date fecha_fin) {
        this.fecha_fin = fecha_fin;
    }
    public Date getCodigo_transaccion() {
        return codigo_transaccion;
    }
    public void setCodigo_transaccion(Date codigo_transaccion) {
        this.codigo_transaccion = codigo_transaccion;
    }
    private String movil;
    private String contador;
    private Date fecha_driver;
    private Date fecha_alta;
    private Date fecha_fin;
    private Date codigo_transaccion;

我的課堂 RespuestaVo

package com.app.validacion.entity;

public class RespuestaVo {

    private String code;
    private String result;

    public String getCode() {
        return code;
    }
    public void setCode(String code) {
        this.code = code;
    }
    public String getResult() {
        return result;
    }
    public void setResult(String result) {
        this.result = result;
    }

}

我收到以下錯誤(移動參數必須作為字符串接收,因為在數據庫中它被發現為 Varchar):

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任何人都知道如何解決這個問題? 如果或如果我需要通過存儲過程進行咨詢

更新

使用@Query,修改代碼如下:

package com.app.validacion.dao;

import org.springframework.data.jpa.repository.Query;
import org.springframework.data.jpa.repository.query.Procedure;
import org.springframework.data.repository.CrudRepository;
import org.springframework.data.repository.query.Param;

import com.app.validacion.entity.DriverBonificados;
import com.app.validacion.entity.RespuestaVo;

public interface DriverBonificadosRepository extends CrudRepository<DriverBonificados, Integer> {

    @Query(nativeQuery = true,value = "call ValidacionClienteBonificado(:movil)")
    RespuestaVo validarClienteBonifiado(@Param("movil") String pMovil);
}

我收到以下錯誤:

org.springframework.core.convert.ConverterNotFoundException:找不到能夠從類型 [org.springframework.data.jpa.repository.query.AbstractJpaQuery$TupleConverter$TupleBackedMap] 轉換為類型 [com.app.validacion.entity.RespuestaVo] 的轉換器在 org.springframework.core.convert.support.GenericConversionService.handleConverterNotFound(GenericConversionService.java:321) ~[spring-core-5.2.1.RELEASE.jar:5.2.1.RELEASE] 在 org.springframework.core.convert。 support.GenericConversionService.convert(GenericConversionService.java:194) ~[spring-core-5.2.1.RELEASE.jar:5.2.1.RELEASE] 在 org.springframework.core.convert.support.GenericConversionService.convert(GenericConversionService.java :174) ~[spring-core-5.2.1.RELEASE.jar:5.2.1.RELEASE] 在 org.springframework.data.repository.query.ResultProcessor$ProjectingConverter.convert(ResultProcessor.java:297) ~[spring- data-commons-2.2.1.RELEASE.jar:2.2.1.RELEASE] 在 org.springframework.data.repository.query.ResultProcessor$ChainingConverter.lam bda$and$0(ResultProcessor.java:217) ~[spring-data-commons-2.2.1.RELEASE.jar:2.2.1.RELEASE] 在 org.springframework.data.repository.query.ResultProcessor$ChainingConverter.convert( ResultProcessor.java:228) ~[spring-data-commons-2.2.1.RELEASE.jar:2.2.1.RELEASE] 在 org.springframework.data.repository.query.ResultProcessor.processResult(ResultProcessor.java:170) ~ [spring-data-commons-2.2.1.RELEASE.jar:2.2.1.RELEASE] 在 org.springframework.data.jpa.repository.query.AbstractJpaQuery.doExecute(AbstractJpaQuery.java:157) ~[spring-data- jpa-2.2.1.RELEASE.jar:2.2.1.RELEASE]

解決了

我設法解決了我的問題,使用 @Query 注釋,並為我將要接收的響應構建了一個接口,在這些情況下有 2 種方法(根據我將接收的參數數量),有了這個,我得到了我在 Json 中的回答,我將界面代碼保留在下面:

public interface RespuestaVo {

    String getCode();
    String getResult();

}

我建議使用 @Query 來運行帶有 Spring Boot 的存儲過程

嘗試這個 -

@GetMapping("/service/{movil}")
public RespuestaVo  ConsultarMovil(@PathVariable("movil") String movil) {
    return dao.validarClienteBonifiado(movil);

}

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