在條件下重置 Angular RXJS 計時器

Question

我有以下代碼

    public timePast:Observable<number>;
    private readonly _stop = new Subject<void>();
    private readonly _start = new Subject<void>();

    this.timePast = timer(1000, 1000).pipe(
            takeUntil(this._stop),
            repeatWhen(() => this._start)
        );

    this.timePast.subscribe(val =>
          {

            console.log(val);
              if(val>=sometime)
              {
                //reset timer
              }

          } );

start(): void {
    this._start.next();
  }
  stop(): void {
    this._stop.next();
  }

如何重置計時器？

Answer 1

您可以反轉開始的部分邏輯：

public timePast: Observable<number> = this._start.pipe(
  switchMap(() => timer(1000, 1000).pipe(takeUntil(this._stop)))
);