在數據庫數據透視表 Laravel 中存儲數據

Question

我有兩個多對多關系的表，由下表連接

我在我的控制器中使用下面的 store 方法，但是當調用它時返回一個錯誤：完整性約束違規：1048 列 'thought_journal_entry_id' 不能為空（SQL：插入到thought_journal_entry_emotions （ emotion_id ， thought_journal_entry_id ）值（1 thought_journal_entry_id ））

我知道thought_journal_entry_id沒有 id，但我不確定如何找到它。 嘗試$entry = ThoughtJournalEntry::find(1)它可以工作，但我需要為 ThoughtJournalEntry $entry = new ThoughtJournalEntry新實例存儲數據 我該怎么做？

public function store(Request $request)
    {
        $this->validate($request, [
            'thought_entry' => 'required'
        ]);

        $entry = new ThoughtJournalEntry;
        $entry->user_id = auth()->user()->id;
        $entry['entry_date'] = date('Y-m-d H:i');
        $entry->thought = $request->input('thought_entry');
        $emotions = $request->has('emotions') ? $request->get('emotions') : [];
        $emotions2 = Emotions::find($emotions);
        $entry->emotions()->sync($emotions2);
        $entry->tt_id = $request->has('thinking_traps') ? $request->get('thinking_traps') : [];
        $entry->balanced_thought = $request->input('balanced_thought');
        $entry->save();

        return redirect('/dashboard');
    }

Answer 1

您需要先保存ThoughtJournalEntry $entry模型以獲取 id。 然后將情緒同步到入口

public function store(Request $request)
    {
        $this->validate($request, [
            'thought_entry' => 'required'
        ]);

        $entry = new ThoughtJournalEntry;
        $entry->user_id = auth()->user()->id;
        $entry['entry_date'] = date('Y-m-d H:i');
        $entry->thought = $request->input('thought_entry');
        $emotions = $request->has('emotions') ? $request->get('emotions') : [];

        $entry->tt_id = $request->has('thinking_traps') ? $request->get('thinking_traps') : [];
        $entry->balanced_thought = $request->input('balanced_thought');
        $entry->save();

        $emotions2 = Emotions::find($emotions);
        $entry->emotions()->sync($emotions2);

        return redirect('/dashboard');
    }