如何用數組初始化結構數組？

Question

我有以下代碼，但我在初始化時遇到問題。 如何用數組初始化結構數組？

typedef struct
{
    UINT8_T ID;
    string CN;
} CU_ContractDesc;

typedef struct
{
    UINT8_T DataType;
    UINT8_T DataSize;
    string SignalName; //This used only for debugging
    UINT8_T NrCont;
    CU_ContractDesc Contracts [];
} CU_BusDesc;

CU_BusDesc BusItems[]={
     {SS_SINGLE, sizeof(single_T), "S1", 1, {{99, "GV1"}}},
     {SS_UINT32, sizeof(uint32_T), "S2", 1, {{99, "GV1"}, {1, "GV2"}}}
};

Answer 1

如果數組大小是固定的，則必須指定其大小：

struct CU_BusDesc
{
    UINT8_T DataType;
    UINT8_T DataSize;
    string SignalName; //This used only for debugging
    UINT8_T NrCont;
    CU_ContractDesc Contracts [2];
};

或者

struct CU_BusDesc
{
    UINT8_T DataType;
    UINT8_T DataSize;
    string SignalName; //This used only for debugging
    UINT8_T NrCont;
    std::array<CU_ContractDesc, 2> Contracts;
};

CU_BusDesc BusItems[]={
     {SS_SINGLE, sizeof(single_T), "S1", 1, {{{99, "GV1"}}}},
     {SS_UINT32, sizeof(uint32_T), "S2", 1, {{{99, "GV1"}, {1, "GV2"}}}}
};

請注意， std::array初始化需要額外的大括號。

如果數組不是固定大小，則應使用std::vector ，c++ 不支持具有未指定大小的數組的結構：

struct CU_BusDesc
{
    UINT8_T DataType;
    UINT8_T DataSize;
    string SignalName; //This used only for debugging
    UINT8_T NrCont;
    std::vector<CU_ContractDesc> Contracts;
};

這將適用於您的原始初始化程序。