[英]Pass JSON to Firebase Dynamic Link
我希望我的用戶在單擊 Firebase 動態鏈接 (FDL) 時導航到我的網頁(起始頁),而我的應用程序用戶則轉到特定頁面(這里我需要額外的 JSON 數據)。
這是我的代碼:
val dynamicLink = FirebaseDynamicLinks.getInstance().createDynamicLink()
.setLink(Uri.parse("{products:...some custom JSON}"))
.setDomainUriPrefix("https://mydomain.page.link")
.setAndroidParameters(DynamicLink.AndroidParameters.Builder().build()) //if set, a click on dynamic link will open android app
.setIosParameters(DynamicLink.IosParameters.Builder("com.foodhatapp.foodhatios").build())
.setSocialMetaTagParameters(DynamicLink.SocialMetaTagParameters.Builder()
.setTitle("Bismillah, FOODHHAAAT")
.setDescription("please click and order at foodhat!")
.setImageUrl(Uri.parse("http://h2866694.stratoserver.net/foodhat/images/products/62-1733-1f644aa6-30af-4237-9478-68a114d7600f.png"))
.build())
.buildShortDynamicLink()
.addOnSuccessListener {
i("teeeeest", it.shortLink.toString())
}
.addOnFailureListener {
i("teeeeest", "error at creating dynamic link...show popup to user..." +
"maybe his internet is broken etc... please check your internet connection and try again later")
}
如您所見,我正在嘗試在 setLink()-Section 中傳遞 JSON...但是我在哪里可以正確傳遞 JSON?
我收到一個FailureException
我知道 setLink() 需要一個格式良好的 URI ......但我想將 JSON 傳遞給我的應用程序,而對於網絡,只需導航到起始頁,這樣網頁的根 URL ......
如何意識到這一點?
您可以像這樣在鏈接本身中附加您的 json 數據...
String json = "{}";//convert your json into string
String link = "http://yourdomainlink.com/?jsondata=" + json;
設置鏈接
.setLink(Uri.parse(link));
然后像這樣檢索json(代碼在java中)
FirebaseDynamicLinks.getInstance()
.getDynamicLink(getIntent())
.addOnSuccessListener(this, new OnSuccessListener<PendingDynamicLinkData>() {
@Override
public void onSuccess(PendingDynamicLinkData pendingDynamicLinkData) {
// Get deep link from result (may be null if no link is found)
Uri deepLink = null;
if (pendingDynamicLinkData != null) {
deepLink = pendingDynamicLinkData.getLink();
String json = deepLink.getQueryParameter("jsondata");
}
}
});
希望這可以幫助
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.