![](/img/trans.png)
[英]VBA code to copy cells in specific column and paste (value) it to cells in specific column on another Sheet based on conditions
[英]Trying to Copy column and paste into another sheet based on another cells value VBA
僅當另一個單元格等於“是”時,我才嘗試復制列的內容。 如果單元格等於“是”,我想將選定的列范圍粘貼到另一個工作簿中。 然后循環到下一個“是”。
If M2 = "Yes" then copy AD2:AD200 if "NO" go to the next "if"
If M3 = "Yes" then copy AE2:AE200 if "NO" go to the next "if"
If M4 = "Yes" then copy AF2:AF200 if "NO" go to the next "if"
等等....
我要尋找的最后一個是 M11。
然后將復制范圍粘貼到“質量檢查狀態中的案例”表中的最后一個空白單元格,
range("AL200",range("al200").end(xlUp).select
這是我到目前為止:
Sheets("Sheet1").Select
If Range("M8").Value = True Then
Range("aj2:aj200").Select
Selection.Copy
Sheets("Cases in QA Status").Select
End If
End Sub
您可以嘗試以下方法嗎?
If Sheets("Sheet1").Range("M8").Value = True Then
Sheets("Sheet1").Range("aj2:aj200").Copy
ActiveSheet.Paste Destination:=Sheets("Cases in QA Status").Range("A1")
End If
並重復其他列:)。
當然,如果列中有 "Yes" ,則將True
替換為"Yes"
。
Sub test()
Dim Ws As Worksheet, toWs As Worksheet
Dim vDB As Variant, rngDB As Range
Dim Target As Range
Dim i As Long
Set Ws = Sheets("Sheet1")
Set toWs = Sheets("Cases in QA Status")
With Ws
vDB = .Range("m2", .Range("m" & Rows.Count).End(xlUp))
End With
For i = 1 To UBound(vDB, 1)
If vDB(i, 1) = "Yes" Then 'vDB(i, 1) = True then
Set rngDB = Ws.Range("ad2").Resize(199).Offset(, i - 1)
Set Target = toWs.Range("al" & Rows.Count).End(xlUp).Offset(1, 0)
rngDB.Copy Target
End If
Next i
End Sub
Sub test2()
Dim Ws As Worksheet, toWs As Worksheet
Dim vDB As Variant, vData As Variant
Dim Target As Range
Dim i As Long
Set Ws = Sheets("Sheet1")
Set toWs = Sheets("Cases in QA Status")
With Ws
vDB = .Range("m2", .Range("m" & Rows.Count).End(xlUp))
End With
For i = 1 To UBound(vDB, 1)
If vDB(i, 1) = "Yes" Then 'vDB(i, 1) = True then
vData = Ws.Range("ad2").Resize(199).Offset(, i - 1)
Set Target = toWs.Range("al" & Rows.Count).End(xlUp).Offset(1, 0)
Target.Resize(199) = vData
End If
Next i
End Sub
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.